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2 years ago

One student did an experiment with sand, rocks, pebbles, and water. The steps of the experiment are shown below.

1 answer:

3 0

The intended observation in this experiment is to check the flow of water through the cotton cloth when pouring the water through different material (sand, rocks and pebbles).
We will observe that the rate of water flow changes depending on which material it is flowing through.
The used materials in this experiment (sand, rocks and pebbles) are the same as those forming different layers of the earth.

Therefore, based on the above explanation, we can infer that the best answer is:
D. groundwater moves at different rates through different layers of the Earth

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A stationary 1.67-kg object is struck by a stick. The object experiences a horizontal force given by F = at - bt2, where t is th

Usimov [2.4K]

Answer:

$v_{f}$ = 3289.8 m / s

Explanation:

This exercise can be solved using the definition of momentum

I = ∫ F dt

Let's replace and calculate

I = ∫ (at - bt²) dt

We integrate

I = a t² / 2 - b t³ / 3

We evaluate between the lower limits I=0 for t = 0 s and higher I=I for t = 2.74 ms

I = a (2,74² / 2- 0) - b (2,74³ / 3 -0)

I = a 3,754 - b 6,857

We substitute the values of a and b

I = 1500 3,754 - 20 6,857

I = 5,631 - 137.14

I = 5493.9 N s

Now let's use the relationship between momentum and momentum

I = Δp = m $v_{f}$ - m v₀o

I = m $v_{f}$ - 0

$v_{f}$ = I / m

$v_{f}$ = 5493.9 /1.67

$v_{f}$ = 3289.8 m / s

5 0

2 years ago

A man climbs a ladder. Which two quantities can be used to calculate the energy stored of the man at the top of the ladder.

Dvinal [7]

Answer:The answer must be The weight of the man and the vertical distance moved.

Explanation: you calculate it by the force you applied times the distance you moved

8 0

2 years ago

Technician A says that some ABS wheel speed sensors are used as part of the tire pressure monitoring system (TPMS) . Technician

erica [24]

Answer:

The correct answer is C) Technician A and B are both correct.

Explanation:

An anti-lock braking system (ABS) is a vehicle safety system that allows the wheels of a car to maintain tractive contact with the road surface while braking, preventing the wheels from locking up (ceasing rotation) and avoiding uncontrolled skidding. It is an automated system that uses the principles of cadence braking.

Anti-lock braking systems since their invention and introduction, have been improved remarkably in a bid to further improve driver safety and comfort. Recent technology not only prevents wheel lock up under braking, but can also provide data for the on board navigation system, traction control system, emergency brake assist, hill start assist, electronic stability control and the front-to-rear brake bias. None of the above would be possible without wheel speed sensors.

The Tire Pressure Monitoring System (TMPS) is an electronic system in your vehicle that monitors your tire air pressure and alerts you when it falls dangerously low.

Indirect TPMS works with your car’s Antilock Braking System’s (ABS) wheel speed sensors. If a tire’s pressure is low, it will roll at a different wheel speed than the other tires. This information is detected by your car’s computer system, which triggers the dashboard indicator light.

Cheers!

3 0

2 years ago

Read 2 more answers

What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear

faust18 [17]

Answer:

1) The radius of the tire is approximately 0.28966 meters

2) The centripetal force is the force that keeps a body moving on a circular path

Explanation:

1) The linear speed of the automobile tire = 20.0 m/s

The period with which the tire turns = 0.091 s

The period = The time it takes to make a complete turn

Therefore;

The number of turns in 1 second = 1/0.091 ≈ 10.989 turns

The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire

∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire

From the speed of the car, 20.0 m/s, we have;

The distance covered in 1 second = 20.0 meters

Therefore;

10.989 × 2 × π × Radius of the tire = 20.0 meters

Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters

The radius of the tire ≈ 0.28966 meters

2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.

The centripetal force is given by the formula, $F = \dfrac{m \cdot v^2}{r}$

Where;

F = The centripetal force

m = The mass of the object

v = The linear velocity of the object

r = The radius of the rotational motion.

3 0

2 years ago

A square loop of wire with initial side length 10 cm is placed in a magnetic field of strength 1 T. The field is parallel to the

Fofino [41]

Answer:

2 x 10⁻³ volts

Explanation:

B = magnetic of magnetic field parallel to the axis of loop = 1 T

$\frac{dA}{dt}$ = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²

θ = Angle of the magnetic field with the area vector = 0

E = emf induced in the loop

Induced emf is given as

E = B $\frac{dA}{dt}$

E = (1) (20 x 10⁻⁴ )

E = 2 x 10⁻³ volts

E = 2 mV

7 0

2 years ago