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Gre4nikov [31]
1 year ago
11

An object which has a mass of 70 kg is sitting on a cliff 10 m high. Calculate the object's Potential energy. Given g = 10m/s2

Physics
1 answer:
Rina8888 [55]1 year ago
6 0
Answer is a.)

Given: Mass m = 70 Kg   Height  h = 10 m;        g = 10 m/s²

Required. Gravitational Potential Energy or P.E

Formula: P.E = mgh

                     = (70 Kg)(10 m/s²)( 10 m)

              P.E = 7,000 Kg.m²/s² or

              P.E = 7,000 J

     
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2 years ago
When you come within 100 ft of the uncontrolled railroad crossing and you cannot see the tracks for 400 ft in both directions, t
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2 years ago
In coordinates with the origin at the barn door, the cow walks from x 0 to x 6.9 m as you apply a force with x component Fx 320.
Stella [2.4K]

Answer:

-209.42J

Explanation:

Here is the complete question.

A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn door, the cow walks from x = 0 to x = 6.9 m as you apply a force with x-component Fx=−[20.0N+(3.0N/m)x]. How much work does the force you apply do on the cow during this displacement?

Solution

The work done by a force W = ∫Fdx since our force is variable.

Since the cow moves from x₁ = 0 m to x₂ = 6.9 m and F = Fx =−[20.0N+(3.0N/m)x] the force applied on the cow.

So, the workdone by the force on the cow is  

W = ∫₀⁶°⁹Fx dx = ∫₀⁶°⁹−[20.0N+(3.0N/m)x] dx

= ∫₀⁶°⁹−[20.0Ndx - ∫₀⁶°⁹(3.0N/m)x] dx

= −[20.0x]₀⁶°⁹ - [3.0x²/2]₀⁶°⁹

= -[20 × 6.9 - 20 × 0] - [3.0 × 6.9²/2 - 3.0 × 0²/2]

= -[138 - 0] - [71.415 - 0] J = (-138 - 71.415) J

= -209.415 J ≅ -209.42J

5 0
2 years ago
To show that displacement current is necessary to make Ampère's law consistent for a charging capacitor Ampère's law relates the
Sladkaya [172]

Answer: The Ampère -Max-well law

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2 years ago
Your latest invention is a car alarm that produces sound at a particularly annoying frequency of 3600 Hz . To do this, the car a
Alex17521 [72]

Answer:

The capacitance and the inductance can choose for a car-alarm circuit are

C = 215.27 μF

L = 9.078 μH

Explanation:

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To determine the capacitance can use the equation

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Solve to C'

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C=215.27 uF

To find the inductance can use the frequency of the circuit

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Solve to L'

L = \frac{1}{4\pi^2*f^2*C}=\frac{1}{4\pi^2*3600^2*215.27 uF}}

L = 9.078 uH

6 0
1 year ago
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