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Yakvenalex [24]
2 years ago
5

Part E Two forces, of magnitude 4N4N and 10N10N, are applied to an object. The relative direction of the forces is unknown. The

net force acting on the object __________. Check all that apply.
Physics
1 answer:
Sedaia [141]2 years ago
6 0

Answer:

A.) cannot be equal to 5N

Explanation:

Forces are vectors: therefore, when two forces act together on the same object, in order to find the resultant force we must apply the rule of additions for vectors.

Therefore, given two forces F_1,F_2, the magnitude of the resultant force can have:

- A minimum value of |F_1-F_2|, if the two forces have opposite direction

- A maximum value of |F_1+F_2|, if the two forces have same direction

In this problem, the two forces that we have are

F_1=4 N\\F_2=10 N

Therefore, the minimum and maximum magnitude of the net force is

F_{min}=|4-10|=6 N\\F_{max}=|4+10|=14 N

So the correct statement is

A.) cannot be equal to 5N

Other statements are wrong because:

B.) cannot be equal to 10N --> 10 N is between the interval 6-14 N

C.) cannot be directed the same way as the force of 10N --> the net force has the same direction of the 10 N force, if also the 4N force has the same direction

D.) must be greater than 10N  --> the net force can have up to a magnitude of 14 N

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shusha [124]

Answer:

19.99 kg m²/s

Explanation:

Angular Momentum (L) is defined as the product of the moment of Inertia (I) and angular velocity (w)

L = m r × v.

r and  v are perpendicular to each other,

where r = lsinθ.

l = 2.4 m

θ= 34°

g = 9.8 m/s²  and m = 5 kg

resolving using newtons second law in the vertical and horizontal components.

T cos θ − m g = 0

T sin θ − mw² lsin θ = 0

where T is the force with which the wire acts on the bob

w = √g / lcosθ

= √ 9.8 / 2.4 ×cos 34

= 2.2193 rad/s

the angular momentum  L = mr× v

= mw (lsin θ)²

= 5 × 2.2193 (2.4 ×sin 34°)²

=19.99 kg m²/s

8 0
2 years ago
A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, take
adell [148]

Answer:

F_{x}=2.31N to the right.

F_{y}=2.1N to in the upwards direction.

Explanation:

In order to solve this problem, we must first start by drawing a diagram of the situation. (See attached diagram).

So, remember that a force is determined by multiplying the mass of the parcticle by its acceleration:

F=ma

so in order to find the components of the force, we need to start by finding its acceleration.

Acceleration is found by using the following formula:

a=\frac{V_{f}-V{0}}{t}

so we can subtract the two vectors, like this:

a=\frac{(6.00i+4.0j)m/s-1.60i m/s}{8s}

which yields:

a=\frac{(4.4i+4.0j)m/s}{8s}

or:

a=(0.55i + 0.5j) m/s^{2}

so now I can find the components of the force:

F=(4.2kg)(0.55i + 0.5j) m/s^{2}

which yields:

F=(2.31i+2.1j)N

so the components of the force are:

F_{x}=2.31N to the right.

F_{y}=2.1N to in the upwards direction.

6 0
2 years ago
While practicing S-turns, a consistently smaller half-circle is made on one side of the road than on the other, and this turn is
erica [24]

Answer:

The answer is "4-5-6 because the bank is growing too quickly in the beginning of its turn".

Explanation:

The S-turns is also known as the reference technique, in which the ground track of the aircraft on both sides of a defined ground-based straight-line distance represents 2 different but equivalent circles.  

Throughout the S-turns, on either side of the road, a progressively smaller half-circle is formed, and this turn does not stop until the road or reference line is crossed during the early part of the turn, the twists increase too quickly.

5 0
1 year ago
After an eye examination, you put some eyedrops on your sensitive eyes. The cornea (the front part of the eye) has an index of r
mina [271]

Answer:

t = 103.45 n m

Explanation:

given,

refractive index of cornea = 1.38

refractive index of eye drop = 1.45

wavelength of refractive index = 600 nm

refractive index of eye drop is greater than refractive index of cornea and the air.

Formula used in this case

for constructive interference

2 n t = (m + \dfrac{1}{2})\lambda

At m = 0 for the minimum thickness, so

2\times 1.45 \times t = (0 + 0.5)\times 600

2.9 \times t =300

t =\dfrac{300}{2.9}

t = 103.45 n m

the minimum thickness of the film of eyedrops t = 103.45 n m

6 0
2 years ago
An electric heater draws a steady current = 20.0 A on a 120-V line. (a) Calculate how much power does it require.
babymother [125]

Answer:

The heater power required is 2400 W. The power in the heater can be calculated as the product of the voltage line and the steady current:

P=V.I

P=120 V * 20 A = 2400 VA = 2400 W

Explanation:

8 0
2 years ago
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