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Yakvenalex [24]
2 years ago
5

Part E Two forces, of magnitude 4N4N and 10N10N, are applied to an object. The relative direction of the forces is unknown. The

net force acting on the object __________. Check all that apply.
Physics
1 answer:
Sedaia [141]2 years ago
6 0

Answer:

A.) cannot be equal to 5N

Explanation:

Forces are vectors: therefore, when two forces act together on the same object, in order to find the resultant force we must apply the rule of additions for vectors.

Therefore, given two forces F_1,F_2, the magnitude of the resultant force can have:

- A minimum value of |F_1-F_2|, if the two forces have opposite direction

- A maximum value of |F_1+F_2|, if the two forces have same direction

In this problem, the two forces that we have are

F_1=4 N\\F_2=10 N

Therefore, the minimum and maximum magnitude of the net force is

F_{min}=|4-10|=6 N\\F_{max}=|4+10|=14 N

So the correct statement is

A.) cannot be equal to 5N

Other statements are wrong because:

B.) cannot be equal to 10N --> 10 N is between the interval 6-14 N

C.) cannot be directed the same way as the force of 10N --> the net force has the same direction of the 10 N force, if also the 4N force has the same direction

D.) must be greater than 10N  --> the net force can have up to a magnitude of 14 N

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Answer:

The water will flow at a speed of 3,884 m/s

Explanation:

Torricelli's equation

v = \sqrt{2gh}

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v = \sqrt{2*9,8m/s^2*0,77m} = 3,884 m/s

6 0
2 years ago
Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
2 years ago
. A horizontal steel spring has a spring constant of 40.0 N/m. What force must be applied to the spring in order to compress it
ANEK [815]

Ans    4 more to be exact

Explanation:

7 0
2 years ago
A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el
ollegr [7]
The answer:
the relationship between elementary charge, potential difference and electrical potential energy is given by 
   E= qV
E:  lectrical potential energy
q:   elementary charge
V:   potential difference

but we have  e=abs val(q)=3 
so we have E= qV=3ex4.5V=<span>13.5 eV
</span>
the answer is <span>(4)13.5 eV</span>

8 0
2 years ago
A badger is trying to cross the street. Its velocity vvv as a function of time ttt is given in the graph below where rightwards
Mrrafil [7]

Answer: -2.5

Explanation:

1/2(-5)= -2.5

-2.5(1)= -2.5

Got it right in Khan Academy. You’re welcome.

5 0
2 years ago
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