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Hunter-Best [27]
2 years ago
8

In a given city, the permissible limit of CO (carbon monoxide) in the air is 100 parts per million (ppm). The city monitors the

steady rise of CO from various sources annually. In which year (rounded off to the nearest integer) will the CO level exceed the permissible limit?
Physics
2 answers:
Roman55 [17]2 years ago
8 0
The city monitors the steady rise of CO from various sources annually. In the year "C: 2019"<span> (rounded off to the nearest integer) will the CO level exceed the permissible limit.

If this isn't the answer, let me know and i'll figure out what it is. But I believe this is it.           :) </span>
siniylev [52]2 years ago
5 0
The correct answer is c.



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A child is sliding a toy block (with mass = m) down a ramp. The coefficient of static friction between the block and the ramp is
tiny-mole [99]

Answer:

F=mg(sin(\theta )-0.25 cos(\theta ))

Explanation:

The free body diagram of the block on the slide is shown in the below figure

Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces

N is the reaction force between the block and the slide

For equilibrium along x-axis we have

\sum F_{x}=0\\\\mgsin(\theta )-\mu N-F=0\\\therefore F=mgsin(\theta)-\mu N......(\alpha )\\Similarly\\\sum F_{y}=0\\\\N-mgcos(\theta )=0\\\therefore N=mgcos(\theta ).......(\beta )\\\\

Using value of N from equation β in α we get value of force as

F=mg(sin(\theta )-\mu cos(\theta ))

Applying values we get

F=mg(sin(\theta )-0.25 cos(\theta ))

8 0
2 years ago
Read 2 more answers
An object of mass M is dropped near the surface of Earth such that the gravitational field provides a constant downward force on
marysya [2.9K]

Answer:

The answer is: c. It does not move

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Because the gravitational force is characterized by being an internal force within the Earth-particle system, in this case, the object of mass M. And since in this system there is no external force in the system, it can be concluded that the center of mass of the system will not move.

6 0
2 years ago
A person wants to lose weight by "pumping iron". The person lifts an 80 kg weight 1 meter. How many times must this weight be li
statuscvo [17]

Answer:

37357 sec  

or 622 min

or 10.4 hrs

Explanation:

GIVEN DATA:

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1 cal = 4184 J

from information given in question we have

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= 14.644 x 10^6 J  

Energy burns in 1 lift = m g h

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lifts required = \frac{(14.644 x 10^6)}{784}

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from the question,

1 lift in 2 sec.

so, total time = 18679 x 2 = 37357 sec  

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3 0
2 years ago
Two cars start 200 m apart and drive toward each other at a steady 10 m/s. On the front of one of them, an energetic grasshopper
vladimir1956 [14]

Answer:

Total distance does the grasshopper travel before the cars hit is 150 m

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8 0
2 years ago
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