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kobusy [5.1K]
2 years ago
11

A student is asked to describe the path of a paper airplane that is thrown in the classroom. Which statement best describes the

path of the paper airplane?
1. The paper airplane will move in a straight line, according to Newton’s first law of motion.
2. The paper airplane will drop straight to the ground once its inertia gives in to the force of gravity.
3. The paper airplane will create a curved path toward the floor as it is pulled toward Earth’s center.
4. The paper airplane will orbit around the desk because it is the object with the largest mass in the room.
Physics
2 answers:
emmasim [6.3K]2 years ago
4 0

Answer: The paper airplane will create a curved path towards the floor as it is pulled toward <u><em>Earth's center.</em></u>

Explanation: The paper airplane will be pulled to the center because <u><em>Earth has a much greater mass than objects on its surface.</em></u> And it will curve because of the amount of <u><em>force</em></u> you are putting onto the plane.

Levart [38]2 years ago
3 0
Answer: The paper airplane will create a curved path toward the floor as it is pulled toward the Earth’s center.
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Maverick and goose are flying a training mission in their F-14. They are flying at an altitude of 1500 m and are traveling at 68
den301095 [7]

Answer:

The bomb will remain in air for <u>17.5 s</u> before hitting the ground.

Explanation:

Given:

Initial vertical height is, y_0=1500\ m

Initial horizontal velocity is, u_x=688\ m/s

Initial vertical velocity is, u_y=0(\textrm{Horizontal velocity only initially)}

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is S=y-y_0=0-1500=-1500\ m

Acceleration in the vertical direction is due to gravity, g=-9.8\ m/s^2

Therefore, the displacement of the bomb is given as:

S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s

So, the bomb will remain in air for 17.5 s before hitting the ground.

6 0
2 years ago
How long does it take for Saturn's equatorial flow, moving at 1500km/h, to encircle the planet?
Ludmilka [50]

Answer:

252.45 hours or 908820 seconds

Explanation:

The equatorial radius of Saturn is 60,268 km

The length of the equator will be circumference

2\pi 60268

Speed of the equatorial flow = 1500 km/h

Time=\dfrac{Distance}{Speed}\\\Rightarrow Time=\dfrac{2\pi 60268}{1500}\\\Rightarrow Time=252.45\ h=252.45\times 60\times 60=908820\ s

It will take 252.45 hours or 908820 seconds for the equatorial flow to encircle the planet.

4 0
1 year ago
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ICE Princess25 [194]

Answer:

Option b. it has the same position and the same acceleration as A

Explanation:

Let's analyze every statement:

a. it has the same position and the same velocity as A

In the instant where B passes A, they Do have the same position. Velocity however, cannot be the same because if they were, ball B would never pass ball A. So, this is false.

b. it has the same position and the same acceleration as A

As we said in the previous option, the position is the same. The acceleration is gravity for both balls, so this is true.

c. it has the same velocity and the same acceleration as A

Acceleration is the same but velocities are not, so this is false.

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The distance they have traveled is the same, so the displacement is the same, but the velocity is not, so this is false.

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7 0
2 years ago
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