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1 year ago

How long does it take for Saturn's equatorial flow, moving at 1500km/h, to encircle the planet?

Physics

2 answers:

kirill115 [55]1 year ago

6 0

Answer:

The time taken will be 243.92 hours.

Explanation:

Given that,

Velocity = 1500 km/h

We know that,

The radius of Saturn is 58232 km.

We need to calculate the circumference of Saturn

Using formula of circumference

$C= 2\pi r$

Pu the value into the formula

$C=2\pi\times 58232$

$C=365882.44\ km$

We need to calculate the time

Using formula of distance

$v = \dfrac{d}{t}$

$t=\dfrac{d}{v}$

Where, d = circumference

v = velocity

Put the value into the formula

$t=\dfrac{365882.44}{1500}$

$t=243.92\ hours$

Hence, The time taken will be 243.92 hours.

Ludmilka [50]1 year ago

4 0

Answer:

252.45 hours or 908820 seconds

Explanation:

The equatorial radius of Saturn is 60,268 km

The length of the equator will be circumference

$2\pi 60268$

Speed of the equatorial flow = 1500 km/h

$Time=\dfrac{Distance}{Speed}\\\Rightarrow Time=\dfrac{2\pi 60268}{1500}\\\Rightarrow Time=252.45\ h=252.45\times 60\times 60=908820\ s$

It will take 252.45 hours or 908820 seconds for the equatorial flow to encircle the planet.

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Kisachek [45]

Answer:

$B_2 = 1.71 mT$

Explanation:

As we know that the magnetic field near the center of solenoid is given as

$B = \frac{\mu_0 N i}{L}$

now we know that initially the length of the solenoid is L = 18 cm and N number of turns are wounded on it

So the magnetic field at the center of the solenoid is 2 mT

now we pulled the coils apart and the length of solenoid is increased as L = 21 cm

so we have

$\frac{B_1}{B_2} = \frac{L_2}{L_1}$

now plug in all values in it

$\frac{2.0 mT}{B_2} = \frac{21}{18}$

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1 year ago

You are sitting on the beach and wondering about the properties of mechanical waves. Describe them in terms of ocean waves.

Rudiy27

Answer:

The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region

Explanation:

A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.

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2 years ago

Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87×106km fr

Andreas93 [3]

Answer:

3494444444.44444 J

-87077491.39453 J

Explanation:

M = Mass of Earth = $6.371\times 10^{6}\ kg$

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

R = Radius of Earth = $6.371\times 10^{6}\ m$

h = Altitude = $2.87\times 10^9\ m$

m = Mass of satellite = 629 kg

v = Velocity of spacecraft = $1.2\times 10^4\ km/h$

The kinetic energy is given by

$K=\frac{1}{2}629\times \left(1.2\times 10^4\times \dfrac{1000}{3600}\right)^2\\\Rightarrow K=3494444444.44444\ J$

The spacecraft's kinetic energy relative to the earth is 3494444444.44444 J

Potential energy is given by

$U=-\dfrac{GMm}{R_e+h}\\\Rightarrow U=-\dfrac{6.67\times 10^{-11}\times 5.97\times 10^{24}\times 629}{2.87\times 10^9+6.371\times 10^{6}}\\\Rightarrow U=-87077491.39453\ J$