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Murljashka [212]
2 years ago
14

A 4.0 Ω resistor, an 8.0 Ω resistor, and a 12.0 Ω resistor are connected in parallel across a 24.0 V battery. What is the equiva

lent resistance of the circuit? Answer in units of Ω.
What is the current in the 4.0 Ω resistor? Answer in units of A.
What is the current in the 8.0 Ω resistor? Answer in units of A.
Physics
2 answers:
LekaFEV [45]2 years ago
5 0
<h2>Answer:</h2>

<u>The Equivalent resistance is 2.17 Ohms</u>

<u>The current in 4 ohm resistor is 6 amps</u>

<u>The current in 4 ohm resistor is 3 amps</u>

<u />

<h2>Explanation:</h2><h3>Part 1</h3>

Equivalent resistance in parallel is given as

1/Re = 1/R1 + 1/R2  + 1/R3

By putting the values

1/Re = 1/4 + 1/8 + 1/12

Equivalent Resistance = 2.17 ohm

<h3>Part 2</h3>

By Using Ohm Law

V = IR

I = V/R

I = 24/4

I = 6 amp

<h3>Part 3</h3>

According to Ohms law

V = IR

I = V/R

I = 24/ 8

I = 3 amp

dsp732 years ago
3 0

PART A)

Equivalent resistance in parallel is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

now we have

\frac{1}{R} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12}

R = 2.18 ohm

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

for 4 ohm resistance we have

24 = 4(i)

i = 6 A

PART C)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

for 8 ohm resistance we have

24 = 8(i)

i = 3 A

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Hi there!

The gravitational force is calculated as follows:

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