Answer:
0.456033049
Explanation:
where N=mg hence
where m is mass of object, g is acceleration due to gravity whose value is taken as 
, 
is the coefficient of static friction and F is the applied force.
Making the subject we obtain
and substituting m for 38 Kg, g for and 170 N for F we obtain
Therefore, the coefficient of static friction is 0.456033049
Answer:
The starting position of the runner.
Explanation:
When you look at the graph, you can see that the first point on the graph is twenty on the y-axis.
The runner starts at twenty, and ends at thirty.
Therefore, the runner starts at twenty on the y-axis, so it's the starting position of the runner.
Answer:
A = -0.576 μC
B = 4.256 μC
Explanation:
Suppose a single electron charge is 
. Then the total charge that is flowing from B to A is:
Let A and B be the initial charge of spheres A and B, respectively. Since the net charge is 3.68μC we have the following equation
(1)
When they touch 2.416μC flows from B to A, then they are equal, so we have the following equation
(2)
Add equation (1) to equation (2) we have
Answer:
3.6 m
Explanation:
let x = horizontal distance between emily and allison should be for allison to catch the ball
Find horizontal speed of the ball
vx = 12 sin 30 = 12 x 0.5 = 6 m/s
To find time taken, we will use vertical values of the ball motion
Initial velocity in vertical direction
u = 12 cos 30 = 10.392 m/s
let a = g = 9.8m/s2
Use equation of motion
s = ut +1/2at^2
s = vertical distance = 8
8 = (10.392)t + (1/2)(9.8)t^2
8 = (10.392)t + (4.9)t^2
4.9t^2 + 10.392t - 8 = 0
Using formula of quadratic or calculator, we'll find
t = 0.6 and t = -2.72
We pick t=0.6s since it's not logical time in negative
Assuming no air resistance or external forces, the ball will move 6m/s horizontally. Hence using the formula of speed
speed vx = distance x / time
x = (vx)(t)
= 6 x 0.6
= 3.6 m
