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2 years ago

The ionization energy of singly charged anions _ as electron affinity of the neutral atom _

Physics

1 answer:

eimsori [14]2 years ago

3 0

Answer:

The ionization energy of an atom is the required amount of energy which is provided to the atom, so, that the required number of electrons are removed from outermost shells of the electronic configuration of the atom. It is minimum amount of energy that is required by the atom, so, that it can remove the charged particle from its outer shell.
The ionization energy of singly charged anions <u>less same</u> as electron affinity of the neutral atom for <u>the electrons.</u>

As, for the anion having the net charge on its body will have larger size then any other normal atom, as the atom will have large and it will be difficult for the nucleus to hold off its whole electronic configuration into one place. This process makes it more easy for the foreign source or agent to remove the required number of charged particles from the atom's outer region.
While it may be same as the phenomenon which occurs inside the neutral atom's whole structure, as there is less affinity for the electrons and that is how the two of them are termed as inter related to one another in the mechanism of having the less affinity for the electrons.

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A transmission channel is made up of three sections. The first section introduces a loss of 16dB, the second an amplification (o

AlekseyPX

Answer:

$P_{out} = 0.100 W = 100 mW$

Explanation:

The attached image shows the system expressed in the question.

We can define an expression for the system.

The equivalent equation for the system would be

$G_{total} = G_{1} + G_{2} + G_{3}\\G_{total} = -16dB+20dB-10 dB = -6 dB$

so, the input signal could be expressed in dB terms

$P_{in} [dB] = 10 log_{10}(P_{in}) \\P_{in} [dB] = 10 log_{10}(0.4)\\P_{in} [dB] = -3.97 dB$ (1)

so the output signal could be expressed as.

$P_{out} = P_{in} + G_{1} + G_{2} + G_{3}\\P_{out} = -3.97 dB - 6dB = -9.97 dB$

The gain should be expressed in dB terms and power in dBm terms so

$P_{out} = -9.97 + 30 = 20.03 dBm$

using the (1) equation to find it in terms of Watts

$P_{out} = 0.100 W = 100 mW$

3 0

2 years ago

Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is

Oksi-84 [34.3K]

Answer:

Explanation:

Heat capacity A = 3 x heat capacity of B

initial temperature of A = 2 x initial temperature of B

TA = 2 TB

Let T be the final temperature of the system

Heat lost by A is equal to the heat gained by B

mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)

heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)

3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB)

3 TA - 3 T = T - TB

6 TB + TB = 4 T

T = 1.75 TB

8 0

2 years ago

Determine the centripetal force upon a 40-kg child who makes 10 revolution around the cliffhanger in 29.3 seconds.the radius of

zysi [14]

Answer:

The centripetal force acting on the child is 39400.56 N.

Explanation:

Given:

Mass of the child is, $m=40\ kg$

Radius of the barrel is, $R=2.90\ m$

Number of revolutions are, $n =10$

Time taken for 10 revolutions is, $t=29.3\ s$

Therefore, the time period of the child is given as:

$T=\frac{n}{t}=\frac{10}{29.3}=0.341\ s$

Now, angular velocity is related to time period as:

$\omega=\frac{2\pi}{T}=\frac{2\pi}{0.341}=18.43\ rad/s$

Now, centripetal force acting on the child is given as:

$F_{c}=m\omega^2 R\\F_{c}=40\times (18.43)^2\times 2.90\\F_{c}=40\times 339.66\times 2.90\\F_{c}=39400.56\ N$

Therefore, the centripetal force acting on the child is 39400.56 N.

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2 years ago

Which statement about images is correct? a) A virtual image cannot be formed on a screen. b) A virtual image cannot be viewed by

ankoles [38]

Answer:

A). A virtual image cannot be formed on a screen.

Explanation:

A virtual image can not be formed on a screen.

For image:

1.A virtual image can be viewed by the unaided eye.

2. A real image must be erect or maybe inverted.

3.Mirrors can produce virtual as well as real image ,it depends on which type of mirror is.

4.A virtual image can be photographed.

So the option A is correct.

5 0

2 years ago

Two students grab a slinky and start waving it up and down. A third student counts the number of waves that pass by every second

deff fn [24]

Velocity = frequency * wavelength

v = fλ, Just pick any points on the graph for frequency f and corresponding λ. Taking the first red point at the top. λ = 6m, f = 1 Hz, v = 6 * 1, v = 6 m/s

V = 6 M/S

4 0

2 years ago

Read 2 more answers

The ionization energy of singly charged anions _____ as electron affinity of the neutral atom _____

The ionization energy of singly charged anions _ as electron affinity of the neutral atom _