Question

evaluate the numerical value of the vertical velocity of the car at time t=0.25 s using the expression from part d, where y0=0.75m, α=0.95s^-1, and w=6.3s^-1

Answer 1

Given :

Displacement , y = 0.75 m .

Angular acceleration , $\alpha=0.95\ s^{-2}$ .

Initial angular velocity , $\omega_o=6.3\ s^{-1}$ .

To Find :

The value of vertical velocity after time t = 0.25 s .

Solution :

By equation of circular motion is given by :

$\omega=\omega_o+\alpha t$

Putting all given values we get :

$\omega=6.3+0.95\times 0.25\\\\\omega= 6.5375\ s^{-1}$

Now , vertical velocity is given by :

$v=y\omega\\\\v=0.75\times 6.5375\ m/s\\\\v=4.90\ m/s$

Therefore , the numerical value of the vertical velocity of the car at time t=0.25 s is 4.90 m/s .

Hence , this is the required solution .