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2 years ago

Which is a correct method used in a scientific experiment involving acid and base solutions

Physics

1 answer:

Nuetrik [128]2 years ago

3 0

<span> Adding an indicator to a solution to test its acidity. There weren't options so hope it helps.</span>

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A hummingbird can a flutter its wings 4800 times per minute what is the frequency of wing flutters per second

Scilla [17]

the answer i got is 80 i hope this helpss!!!!

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2 years ago

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In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce

Mandarinka [93]

Answer:

0.22 m

Explanation:

We are told that the driver can survive an acceleration of 50g only if the collision lasts no longer than 30 ms. So,

$t = 30 ms = 0.030 s$

The acceleration is

$a=-50g = -50(9.8)=-490 m/s^2$

where the negative sign is due to the fact that this is a deceleration, since the driver comes to a stop in the collision.

First of all, we can find what the initial velocity of the car should be in this conditions by using the equation:

$v=u+at$

And since the final velocity is zero, v=0, and solving for u,

$u=-at=-490(0.030)=14.7 m/s$

And now we can find the corresponding distance travelled using the equation:

$d=ut+\frac{1}{2}at^2 = (14.7)(0.030)+\frac{1}{2}(-490)(0.030)^2=0.22 m$

8 0

2 years ago

Which trailer has more downward pressure where it attaches to the car?

VARVARA [1.3K]

The one that is loaded worst. The overall weight is not important; tongue weight is a matter of loading. Our 12,000 lb snow cat trailer, which has stops to position the cat properly, has under 100 lbs tongue weight. Excessive tongue weight is a Bad Thing because it reduces weight on the towing vehicle's front wheels, leading to instability.

4 0

2 years ago

A car increases its speed from 9.6 meters per second to 11.2 meters per second in 4.0 seconds. The average acceleration of the c

Gwar [14]

The acceleration is the change of speed/velocity over time. Thus to calculate this you do (V1-V2)/T or (11.2-9.6)/4 or 0.4 m/s^2

5 0

2 years ago

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The magnetic field around the head has been measured to be approximately 3.00×10−8 gauss . Although the currents that cause this

konstantin123 [22]

Answer:

$3.81972\times 10^{-7}\ A$

Explanation:

B = Magnetic field = $3\times 10^{-8}\ G$

d = Diameter of loop = 16 cm

r = Radius = $\frac{d}{2}=\frac{16}{2}=8\ cm$

i = Current

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

The magnetic field of a loop is given by

$B=\frac{\mu_0i}{2r}\\\Rightarrow i=\frac{B2r}{\mu_0}\\\Rightarrow i=\frac{3\times 10^{-8}\times 10^{-4}\times 2\times 0.08}{4\pi\times 10^{-7}}\\\Rightarrow i=3.81972\times 10^{-7}\ A$

The current needed to produce such a field at the center of the loop is $3.81972\times 10^{-7}\ A$

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2 years ago