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SVETLANKA909090 [29]
2 years ago
12

A 480-kilogram horse runs across a field at a rate of 40 km/hr. What is the magnitude of the horse's momentum?

Physics
2 answers:
kirill115 [55]2 years ago
6 0
P=mv
<span>p=480 (40)= 19 200 kg km/hr
Hope this helped! :3</span>
Andrej [43]2 years ago
4 0
Momentum (p) = mass × velocity

so, 480×40 = 19,200 kg km/hr

so the answer is C !!
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The gravitational force exerted on the satellite is called the centrifugal force, the force keeping it orbiting to the planet. Its formula is F= mass times the square of the velocity all over the radius.Thus,

F = 2400 * 6670^2 * (1/8.92x10^6) 
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I hope I was able to help you. Have a good day.
4 0
2 years ago
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A spaceship of frontal area 10 m2 moves through a large dust cloud with a speed of 1 x 106 m/s. The mass density of the dust is
Step2247 [10]

Answer:

The decelerating force is 3\times 10^{- 11}\ N

Solution:

As per the question:

Frontal Area, A = 10\ m^{2}

Speed of the spaceship, v = 1\times 10^{6}\ m/s

Mass density of dust, \rho_{d} = 3\times 10^{- 18}\ kg/m^{3}

Now, to calculate the average decelerating force exerted by the particle:

Mass,\ m = \rho_{d}V                                (1)

Volume, V = A\times v\times t

Thus substituting the value of volume, V in eqn (1):

m = \rho_{d}(Avt)

where

A = Area

v = velocity

t = time

m = \rho_{d}(A\times v\times t)                  (2)

Momentum,\ p = \rho_{d}(Avt)v = \rho_{d}Av^{2}t

From Newton's second law of motion:

F = \frac{dp}{dt}

Thus differentiating w.r.t time 't':

F_{avg} = \frac{d}{dt}(\rho_{d}Av^{2}t) = \rho_{d}Av^{2}

where

F_{avg} = average decelerating force of the particle

Now, substituting suitable values in the above eqn:

F_{avg} = 3\times 10^{- 18}\times 10\times 1\times 10^{6} = 3\times 10^{- 11}\ N

4 0
1 year ago
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Natasha_Volkova [10]

Answer:

Explanation:

Given

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total distance d=200\ m

he swims first 100 m at an average speed if 1.8 m/s

so time taken is t_1=\frac{100}{1.8}=55.55\ s

suppose t_2 is the time taken to swim remaining half

average velocity is v_{avg}=\frac{displacement}{total\ time}

v_{avg}=\frac{100+100}{55.55+t_2}

t_2+55.55=\frac{200}{2}=100

t_2=44.45\ s

so velocity in the second half is

v_2=\frac{100}{45.45}

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3 0
2 years ago
A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo
padilas [110]

Answer:

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Explanation:

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Where m corresponds to the diffraction order

Let's use trigonometry to find the breast

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We replace

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Let's place in the first order m = 1

Let's look for the separation of the lines (d)

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Part B

The compound wavelength B

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