A lady bug moves 10 cm forward and 5 cm backwards
so total distance moved by lady bug = 10 + 5 = 15 cm
total time taken by the lady bug
t = 20 s
so the average speed is given as
so its average speed is 0.75 cm/s
Two events are observed in a frame of reference S to occur at the same space point, with the second event occurring after a time
of 1.70 s . In a second frame S' moving relative to S, the second event is observed to occur after a time of 2.25 s . What is the difference between the positions of the two events as measured in S'?
1 answer:
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