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Gennadij [26K]
1 year ago
15

In a laboratory, Nakisha mixes a sodium hydroxide solution with an indicator called phenolphthalein. When combined, they create

a pink solution. Nakisha wonders if mixing other solutions with phenolphthalein will also create this pink color. How could Nakisha use the scientific inquiry process to determine whether mixing other solutions with phenolphthalein will also create a pink color? Check all that apply. by making qualitative observations about the sodium hydroxide and phenolphthalein in solution by asking a classmate if sodium hydroxide turns pink when mixed with other solutions by comparing the given solution to other familiar solutions containing phenolphthalein by designing an experiment to test phenolphthalein with other solutions by repeating the experiment at different temperatures
Physics
2 answers:
Gnesinka [82]1 year ago
8 0

by making qualitative observations about the sodium hydroxide and phenolphthalein in solution

by comparing the given solution to other familiar solutions containing phenolphthalein

by designing an experiment to test phenolphthalein with other solutions

Lapatulllka [165]1 year ago
8 0

Answer:

1. by making qualitative observations about the sodium hydroxide and phenolphthalein in solution

3. by comparing the given solution to other familiar solutions containing phenolphthalein

4. by designing an experiment to test phenolphthalein with other solutions

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Your latest invention is a car alarm that produces sound at a particularly annoying frequency of 3600 Hz . To do this, the car a
Alex17521 [72]

Answer:

The capacitance and the inductance can choose for a car-alarm circuit are

C = 215.27 μF

L = 9.078 μH

Explanation:

V =12.0 V, E = 1.55*10^2 J, f = 3600 Hz

To determine the capacitance can use the equation

U_c= \frac{1}{2}*C*V^2

Solve to C'

C = \frac{U_c*2}{V^2}=\frac{1.55x10^2J*2}{12.0^2V}

C=215.27 uF

To find the inductance can use the frequency of the circuit

f = \frac{1}{2\pi* \sqrt{C*L} }

Solve to L'

L = \frac{1}{4\pi^2*f^2*C}=\frac{1}{4\pi^2*3600^2*215.27 uF}}

L = 9.078 uH

6 0
1 year ago
Physicists often measure the momentum of subatomic particles moving near the speed of light in units of MeV/c, where c is the sp
maxonik [38]

Answer:

kg m/s

Explanation:

e = Charge = C

V = Voltage = \dfrac{N}{C}m

c = Speed of light = m/s

Momentum is given by

\dfrac{MeV}{c}=\dfrac{e\times V}{c}\\\Rightarrow \dfrac{MeV}{c}=\dfrac{C\times \dfrac{N}{C}\times m}{m/s}\\\Rightarrow \dfrac{MeV}{c}=Ns\\\Rightarrow \dfrac{MeV}{c}=kg\times \dfrac{m}{s}\times s\\\Rightarrow \dfrac{MeV}{c}=kg\cdot m/s

The unit of MeV/c in SI fundamental units is kg m/s

5 0
1 year ago
Use the formula h = −16t2 + v0t. (if an answer does not exist, enter dne.) a ball is thrown straight upward at an initial speed
makkiz [27]
Using the given formula with v0=56 ft/s and h=40 ft 
h = -16t2 + v0t  
40 = -16t2 + 56t 
16t2 - 56t + 40 = 0  
Solving the quadratic equation:  
t= (-b+/-(b^2-4ac)^1/2)/2a = (56+/-((-56)^2-4*16*40)^1/2)/2*16 = (56 +/- 24) / 32 
 We have two possible solutions  
t1 = (56+24)/32 = 2.5 
t2 = (56-24)/32 = 1  
So initially the ball reach a height of 40 ft in 1 second.
3 0
2 years ago
In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of a
fgiga [73]

(a) The diffraction decreases

The formula for the diffraction pattern from a single slit is given by:

sin \theta = \frac{n \lambda}{a}

where

\theta is the angle corresponding to nth-minimum in the diffraction pattern, measured from the centre of the pattern

n is the order of the minimum

\lambda is the wavelength

a is the width of the opening

As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because \theta increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.

(b) 10.8^{\circ}

The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:

sin \theta = \frac{(1) \lambda}{a}

in this case we have

\lambda=54 cm = 0.54 m is the wavelength

a=5.7 m is the width of the opening

Solving the equation, we find

\theta = sin^{-1} (\frac{\lambda}{a})=sin^{-1} (\frac{0.54 m}{5.7 m})=5.4^{\circ}

So the angular spread of the central diffraction maximum is twice this angle:

\theta = 2 \cdot 5.4^{\circ}=10.8^{\circ}

(c) 0.26^{\circ}

Here we can apply the same formula used before, but this time the wavelength of the signal is

\lambda=13 mm=0.013 m

so the angle corresponding to the first minimum is

\theta = sin^{-1} (\frac{\lambda}{a})=sin^{-1} (\frac{0.013 m}{5.7 m})=0.13^{\circ}

So the angular spread of the central diffraction maximum is twice this angle:

\theta = 2 \cdot 0.13^{\circ}=0.26^{\circ}

5 0
1 year ago
The price of coffee fell sharply last month, while the quantity sold remained the same. Five people suggest various explanations
miss Akunina [59]

Answer:

France. True Supply increased and demand did not adapt

Explanation:

If the price of coffee decreases it may be due to two causes

- Increase of the offer

- decrease in demand

- both simultaneously.

Let's examine the statement. They tell us that the amount sold remained constant, so there is no decrease in demand, therefore the only cause may be the increase in supply.

Let's check the answers

Antonio     False. The demand is constant.

Carolina.   False. The demand is constant.

Dmitri        False. The demand is constant.

France.     True Supply increased and demand did not adapt

Jake.         False. Demand did not adapt to the increase in supply

7 0
1 year ago
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