The work done on the wagon is 3549 J
Explanation:
The work done by a force when moving an object is given by
where
:
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and of the displacement
In this problem we have the following data:
F = 87 N is the magnitude of the force
d = 44 m is the displacement of the wagon
is the angle between the direction of the force and the displacement
Substituting, we find the work done
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Answer:
3. none of these
Explanation:
The rotational kinetic energy of an object is given by:
where
I is the moment of inertia
is the angular speed
In this problem, we have two objects rotating, so the total rotational kinetic energy will be the sum of the rotational energies of each object.
For disk 1:
For disk 2:
so the total energy is
So, none of the options is correct.
Answer:
2.25 %
Explanation:
65-95-99.7 is a rule to remember the precentages that lies around the mean.
at the range of mean (
) plus or minus one standard deviation (
), ![P([\mu-\sigma \leq X \leq \mu+\sigma])\approx 68.3%](https://tex.z-dn.net/?f=P%28%5B%5Cmu-%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%2B%5Csigma%5D%29%5Capprox%2068.3%25)
at the range of mean plus or minus two standard deviation, ![P([\mu -2\sigma \leq X \leq \mu+2\sigma])\approx 95.5%](https://tex.z-dn.net/?f=P%28%5B%5Cmu%20-2%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%2B2%5Csigma%5D%29%5Capprox%2095.5%25)
at the range of mean plus or minus three standard deviation, ![P([\mu - 3\sigma\leq X \leq \mu+3\sigma])\approx 99.7%](https://tex.z-dn.net/?f=P%28%5B%5Cmu%20-%203%5Csigma%5Cleq%20X%20%5Cleq%20%5Cmu%2B3%5Csigma%5D%29%5Capprox%2099.7%25)
So, note that they are asking about the probability that it is greater than 0.32, that is the mean (0.3) plus two times the standard deviation (0.1) (
)
So we know that the 95.5% is between 
and 
, hence approximately the 4.5% (100%-95.5%) is greater than 0.32 or less than 0.28. But half (4.5%/2=2.25%) is greater than 0.32 and the other half is less than 0.28.
So 
Answer:
Technician A is right. The situation will happens even with only two bulbs in series
Explanation:
We must take into account that
1.- All electric device need its nominal voltage to operate
2.-Any and all electric device means an electric load for the source in terms of equation that means any device will implies a drop voltage of V = I*R ( I the flows current and R the resistance of the device)
3.-Nominal voltage for bulbs are specify for houses voltages you find between fase and neutral wires for instance in Venezuela 120 (v).
4.-In a imaginary circuit of only one bulb, the nominal voltage will be applied and the bulb will operates correctly, but when you add another bulb (in series) the nominal voltage will split between the two bulbs ( we could find a situation such as the first bulb work properly but the second one does not). The voltage split according to Ohms law (in such way that the sum of voltage between the terminal of the first bulb plus the voltage at terminals of the second one are equal to nominal voltage.
For that reason all the bulbs are connected in parallel in wich case all of them will operate with the common voltage
Answer:
F₁ = F₂ = F₃ = 0 N
Explanation:
given,
Arrow 1 mass = 80 g speed = 10 m/s
Arrow 2 mass = 80 g speed = 9 m/s
Arrow 3 mass = 90 g speed = 9 m/s
Horizontal Force:- F₁ , F₂ and F₃
There is no air resistance.
If Air resistance is zero then the horizontal acceleration of the arrow also equal to zero.
We know,
According to newton's second law
F = m a
If Acceleration is equal to zero
Then Force is also equal to zero.
Hence, F₁ = F₂ = F₃ = 0 N
