Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on
2 answers:
You might be interested in
Starting from the angular velocity, we can calculate the tangential velocity of the stone:
Then we can calculate the angular momentum of the stone about the center of the circle, given by
where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.
Substituting the data of the problem, we find
Then we can calculate the angular momentum of the stone about the center of the circle, given by
where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.
Substituting the data of the problem, we find
Answer:
B_o = 1.013μT
Explanation:
To find B_o you take into account the formula for the emf:
where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.
By applying the derivative you obtain:
when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:
hence, B_o = 1.013μT
Answer:
3.1 m/s²
Explanation:
Given:
Mass of the balloon (m) = 11.4 g = 0.0114 kg ( 1 kg = 1000 g)
Force acting on the balloon (F) = 0.035 N
Acceleration with which the balloon must be hit (a) = ?
Now, we know that, from Newton's second law, net force acting on an object is equal to the product of its mass and acceleration.
Therefore, framing in equation form, we have:
Rewriting in terms of acceleration 'a', we get:
Now, substitute the given values and solve for 'a'. This gives,
Therefore, the acceleration of the water balloon to reach the target must be equal to 3.1 m/s².