Question

In this part of the experiment, you will be changing the speed of the bottle by dropping if from different heights. You will use the same mass, 0.250 kg, for each trial, so record this mass in Table B for each velocity. Then, calculate the expected kinetic energy (KE) at each velocity. Use formula Ke = 1/2mv^2,
where m is the mass and v is the speed. Record your calculations in Table B of your Student Guide.

Answer 1

Answer:

Givens:

• $m=0.250 \ kg$
• The different speeds: $v_{1}=2 \ m/s ;v_{2}=3; m/s; v_{3}=4 \ m/s; v_{4}=5 \ m/s; v_{5}=6 \ m/s$

So, for each speed we will calculate its kinetic energy using its definition:

$K=\frac{1}{2}mv^{2}$

For $v_{1}=2 \ m/s$:

$K_{1}=\frac{1}{2}(0.250 \ kg) (2 \ m/s)^{2}=0.5 \ J$

For v_{2}=3; m/s:

$K_{2}=\frac{1}{2}(0.250 \ kg) (3 \ m/s)^{2}=1.125 \ J$

For v_{3}=4 \ m/s:

$K_{3}=\frac{1}{2}(0.250 \ kg) (4 \ m/s)^{2}=2 \ J$

For v_{4}=5 \ m/s:

$K_{4}=\frac{1}{2}(0.250 \ kg) (5 \ m/s)^{2}=3.125 \ J$

For v_{5}=6 \ m/s:

$K_{5}=\frac{1}{2}(0.250 \ kg) (6 \ m/s)^{2}=4.5 \ J$

So, there you have it, each kinetic energy for each speed. The only procedure we did was to replace given values and solve basic operations, that's it.

Answer 2

Answer:

0.5

1

2

3

5

Explanation: