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artcher [175]
2 years ago
5

Why do most objects tend to contain nearly equal numbers of positive and negative charges?

Physics
2 answers:
KengaRu [80]2 years ago
4 0

Explanation:

Most objects tend to contains nearly equal numbers of negative and positive charges as it is most stable state. In this case, the object does not want to lose or gain electrons in order to get stable.

The repulsive or attractive electrical forces tend to cancel each other.

There are an equal number of positive and negative charges which make the object electrically neutral.

If the object has more negative charge than the positive charge then it makes the object most unstable or vice versa.

mart [117]2 years ago
3 0
<span>Most objects tend to contain the same numbers of positive and negative charge because this is the most stable situation. In fact, if an object has an excess of positive charge, it tends to attract an equal number of negative charges to balance this effect and restore neutrality: the attracted negative charges combine with the excess of positive charges, leaving the object electrically neutral.</span>
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Answer:

a) Velocity = 4.2m/s

b) Acceleration = 2.94m/s^2

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Explanation:

a) Velocity,V=sqrt(2×9.8×0.900)

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a= 4.2^2 - 0/2×3

a= 17.64/6= 2.94m/s^2

c) Newton's 2nd law indicates:

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F= m(g+a)

F=110(9.8+2.94)

F=110×12.94

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1 year ago
Two objects are placed in thermal contact and are allowed to come to equilibrium in isolation. The heat capacity of Object A is
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Answer:

Explanation:

Heat capacity A = 3 x heat capacity of B

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2 years ago
A teacher sets up a stand carrying a convex lens of focal length 15 cm at 20.5 cm mark on the optical bench. She asks the studen
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1 year ago
Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only o
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Answer:

An annular Solar Eclipse

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7 0
2 years ago
Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
1 year ago
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