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alisha [4.7K]
2 years ago
7

You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change

in potential energy of a system containing the book and Earth?
Physics
1 answer:
Sophie [7]2 years ago
8 0
The change in potential energy of an object is given by
U=mg \Delta h
where
m is the mass of the object
g is the gravitational acceleration
\delta h is the increase in altitude of the object

In our problem, m=2.5 kg is the mass of the book, g=9.81 m/s^2 and 
\Delta h=2.6 m -1.2 m=1.4 m is the increase in altitude of the book, so its variation of potential energy is
U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J
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Answer:

88.3

Explanation:

Emf in a rotating coil is given by rate of change of flux:

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N: number of turns in the coil= 80

A: area of the coil= 0.25×0.40= 0.1

B: magnetic field strength= 1.1

Ф: angle of rotation= 90- 37= 53

dt= 0.06s

E= (80 × 0.4× 0.25×1.10 × cos53)/0.06= 88.3V

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What is Yusef most likely finding?
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Explanation:

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4 0
1 year ago
A 2 kg stone is tied to a 0.5 m string and swung around a circle at a constant angular velocity of 12 rad/s. the angular momentu
Illusion [34]
Starting from the angular velocity, we can calculate the tangential velocity of the stone:
v=\omega r= (12 rad/s)(0.5 m)= 6 m/s

Then we can calculate the angular momentum of the stone about the center of the circle, given by
L=mvr
where
m is the stone mass
v its tangential velocity
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Substituting the data of the problem, we find
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3 0
2 years ago
A good quarterback can throw a football at 27 m/s (about 60 mph). If we assume that the ball is caught at the same height from w
bezimeni [28]

Answer:

The ball was in air for 3.896 s

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given,

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v_h  =  v cos θ

v_h  =  27 × cos 45°

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The time to attain maximum height is one half of the time of flight.

v = u + at                     ∵ v = 0 (max. height)

19.09 - 9.8 t₁ = 0

t₁ = 1.948 s

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2 t₁ = 3.896 s

The horizontal distance traveled is

D = v × t

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   = 74.375 m

The ball was in air for 3.896 s

8 0
2 years ago
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