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SpyIntel [72]
2 years ago
12

You slip a wrench over a bolt. Taking the origin at the bolt, the other end of the wrench is at x=18cm, y=5.5cm. You apply a for

ce F? =88i^?23j^ to the end of the wrench. What is the torque on the bolt?
Physics
1 answer:
mart [117]2 years ago
8 0

Answer:

The torque on the wrench is 4.188 Nm

Explanation:

Let r = xi + yj where is the distance of the applied force to the origin.

Since x = 18 cm = 0.18 cm and y = 5.5 cm = 0.055 cm,

r = 0.18i + 0.055j

The applied force f = 88i - 23j

The torque τ = r × F

So, τ = r × F = (0.18i + 0.055j) × (88i - 23j) = 0.18i × 88i + 0.18i × -23j + 0.055j × 88i + 0.055j × -23j

= (0.18 × 88)i × i + (0.18 × -23)i × j + (0.055 × 88)j × i + (0.055 × -22)j × j  

= (0.18 × 88) × 0 + (0.18 × -23) × k + (0.055 × 88) × (-k) + (0.055 × -22) × 0   since i × i = 0, j × j = 0, i × j = k and j × i = -k

= 0 - 4.14k + 0.0484(-k) + 0

= -4.14k - 0.0484k

= -4.1884k Nm

≅ -4.188k Nm

So, the torque on the wrench is 4.188 Nm

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Explanation:

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2 years ago
he drawing shows two perpendicular, long, straight wires, both of which lie in the plane of the paper. The current in each of th
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Answer:

The magnitudes of the net magnetic fields at points A and B is 2.66 x 10^{-6} T

Explanation:

Given information :

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The magnetic of straight-current wire :

B= μ_{0}I/2πr

where

B = magnetic field (T)

μ_{0} = 1.26 x 10^{-6} (N/A^{2})

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the magnetic field at points A and B is the same because both of wires have the same distance. Based on the right-hand rule, the net magnetic field of A and B is canceled each other (or substracted). Thus,

BH = μ_{0}I/2πr

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BV = μ_{0}I/2πr

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hence,

the net magnetic field = BH - BV

                                     = 4.96 x 10^{-6} - 2.3 x 10^{-6}

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Answer:

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Conveniently, the lamp posts in this problem are equally spaced, and we can treat that spacing as our measuring stick. To measure speed, we'll need to bring time in somehow too, and that's where the stopwatch comes in. A good method might go like this:

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