Answer:velocity = 7.26 * 10^6 m/sec
Explanation:The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
To solve this problem it is necessary to use the given proportions of power and energy, as well as the energy conversion factor in Jules to Calories.
The power is defined as the amount of energy lost per second and whose unit is Watt. Therefore the energy loss rate given in seconds was
The rate of energy loss per day would then be,
That is to say that Energy in Jules per lost day is 5356800J
By definition we know that 
In this way the energy in Cal is,
The number of kilocalories (food calories) must be 1279.694 KCal
The magnitude of the force<span> a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away is 1920 Newtons. The formula used to solve this problem is:
F = kq1q2/r^2
where:
F = Electric force, Newtons
k = Coulomb's constant, 9x10^9 Nm^2/C^2
q1 = point charge 1, C
q2 = point charge 2, C
r = distance between charges, meters
Using direct substitution, the force F is determined to be 1920 Newtons.</span>
Answer:
<h2>a)
Nathan's acceleration is 5 m/s²
</h2><h2>b)
Nathan's displacement during this time interval is 15.625 m</h2><h2>
c) Nathan's average velocity during this time interval is 6.25 m/s</h2>
Explanation:
a) We have equation of motion v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = 12.5 m/s
Time, t = 2.5 s
Substituting
v = u + at
1.25 = 0 + a x 2.5
a = 5 m/s²
Nathan's acceleration is 5 m/s²
b) We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 5 m/s²
Time, t = 2.5 s
Substituting
s = ut + 0.5 at²
s = 0 x 2.5 + 0.5 x 5 x 2.5²
s = 15.625 m
Nathan's displacement during this time interval is 15.625 m
c) Displacement = 15.625 m
Time = 2.5 s
We have
Displacement = Time x Average velocity
15.625 = 2.5 x Average velocity
Average velocity = 6.25 m/s
Nathan's average velocity during this time interval is 6.25 m/s
