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aleksandr82 [10.1K]
1 year ago
7

The arm of a crane at a construction site is 17.0 m long, and it makes an angle of 11.6 ◦ with the horizontal. Assume that the m

aximum load the crane can handle is limited by the amount of torque the load produces around the base of the arm. What maximum torque can the crane withstand if the maximum load the crane can handle is 643 N? Answer in units of N · m.
Physics
1 answer:
riadik2000 [5.3K]1 year ago
8 0

Answer:

τ_max ≈ 10,708 N.m

Explanation:

To find max torque, we need the component of force that is perpendicular to the direction of vector r.

Now, Torque is the perpendicular component of the force times the distance.

Thus;

τ_max = F x r

τ_max = (643 cos 11.6°) (17 )

τ_max ≈ 10,708 N.m

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Answer:

Please find the answer in the explanation

Explanation:

Given that A 1.0 g plastic bead, with a charge of -6.0 nC, is suspended between the two plates by the force of the electric field between them.

Since it is suspended, it must have been repelled by the bottom negative plate and trying to be attracted to the top plate.

We can therefore conclude that the upper plate, is positively charged

B.) The charge on the positive plate of parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates must be less than 6.0 nC

3 0
1 year ago
Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a larg
horrorfan [7]

Answer:

The value is t_1 =  9 \  s

Explanation:

Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows

v  =  u   +  at

Here u = 0 \ m/s

a = 13.5 m/s^2

So

v  =  0   +  13.5 *  3.10

=> v  =  41.85 \ m/s

The is distance it covers at this time is

s =  u *  t  +  \frac{1}{2} a *  t^2

=> s =  +  \frac{1}{2} * 13.5 *  3.10^2

=> s =64.87

Now when sled stops its the final velocity is v_f =  0 m/s while the initial velocity will be the velocity after its acceleration i.e v  =  41.85 \ m/s

So

v_f  =  v  +  a_1t_1

Here  a_1 =  - 4.65, the negative sign shows that it is deceleration

So

           0  =  41.85  - 4.65 *  t_1

=> t_1 =  9 \  s

3 0
1 year ago
Now suppose the initial velocity of the train is 4 m/s and the hill is 4 meters tall. If the train has a mass of 30000 kg, what
hoa [83]

Answer:

<h2>187,500N/m</h2>

Explanation:

From the question, the kinectic energy of the train will be equal to the energy stored in the spring.

Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².

Equating both we will have;

1/2 mv² = 1/2ke²

mv² = ke²

m is the mass of the train

v is the velocity of then train

k is the spring constant

e is the extension caused by the spring.

Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m

Substituting this values into the formula will give;

30000*4² =  k*1.6²

k = \frac{30,000*16}{1.6^2}\\ \\k = \frac{480,000}{2.56}\\ \\k = 187,500Nm^{-1}

The value of the spring constant is 187,500N/m

7 0
1 year ago
Which letter correctly identifies the part of the hydrologic cycle that is most directly affected by impervious building materia
masha68 [24]

Infiltration

Explanation:

The component of the hydrologic cycle affected by impervious building such as concrete and asphalt is infiltration.

  • Water infiltration is a major component of the hydrologic cycle.
  • Concretes and other materials can prevent water from going down into the earth.
  • This affects the ground water system in place.
  • It leads to increase in surface run off and might cause inundation of an area.
  • Infiltration is a very important component of water cycle.
  • It takes water to plant root and recharges groundwater systems.
  • Impervious structures takes this capability away.

learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

3 0
2 years ago
1 Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes under identical
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Answer:

YOUR answer is given below:

Explanation:

3 0
1 year ago
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