Answer:
The airspeed must be 7.78 m/s for the rectangular plate kept at 30°.
Explanation:
By looking at the images below wee see that the airspeed on one side of the rectangular plate decreases the statical pressure over this side. Since over the downside, the pressure still bein the atmospheric pressure. This difference in pressure produces a lift force in the plate. The list force is the net force obtained between the difference of the forces that produce the pressure over the upside and the downside:
Where up and down relate to what movement the forces produce. And p and V are the respective air density and velocity.
When the plate is kept horizontal the lift force balance the moment due to the weight of the plate and considering that both forces act at the same point:
By replacing the known values it is possible to find the plate's weight:
When the plate kept to 30° from the vertical the moment equation balance is written as:
The sine of 30° is due to the weight is 30° oriented, therefore the new value for the airspeed is:
Answer: t-trees?
i couldn't find anything on this topic but the only thing i could think of was trees, maybe if you go to a history website you can find a answer there :)
hope i helped a little :)
We know that
g = LcosΘ
<span>where g, L and Θ are centripetal gravity length, and angle of object
</span><span>ω² = g/LcosΘ </span>
<span>ω = √(g / LcosΘ) </span>
Answer:
a) 0.500 s
b) greater than 0.500 s
c) greater than 0.500 s
Explanation:
The time period of an oscillating spring-mass system is given by:
where, m is the mass and k is the spring constant.
a) As the period of oscillation does not depend on the distance by which the mass is pulled, the period would remain same as 0.500 s for the given system.
b) As the period varies inversely with the square root of spring constant, so with the decrease in the spring constant, the period would increase. So, the new period would be greater than 0.500 s.
c) As the period varies directly with the square root of mass, so with the increase in mass, the period will also increase. The new period will be greater than 0.500 s.
