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Butoxors [25]
2 years ago
6

A standard 1 kilogram weight is a cylinder 51.0 mm in height and 42.0 mm in diameter. Determine the density of the material

Physics
1 answer:
worty [1.4K]2 years ago
3 0

Answer:

14160 kg/m^3

Explanation:

First of all, we need to find the volume of the cylinder.

The volume of the cylinder is given by:

V=\pi r^2 h

where:

r=\frac{d}{2}=\frac{42.0 mm}{2}=21.0 mm=0.021 m is the radius

h=51.0 mm=0.051 m is the height

Substituting, we find

V=\pi (0.021 m)^2 (0.051 m)=7.1 \cdot 10^{-5} m^3

And the density is given by

d=\frac{m}{V}

where m = 1 kg is the mass. Substituting, we find

d=\frac{1 kg}{7.1\cdot 10^{-5} m^3}=14,160 kg/m^3

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6 0
2 years ago
For a metal that has an electrical conductivity of 7.1 x 107 (Ω-m)-1, do the following: (a) Calculate the resistance (in Ω) of a
jonny [76]

Answer:

(a) 0.0178 Ω

(b) 3.4 A

(c) 6.4 x 10⁵ A/m²

(d) 9.01 x 10⁻³ V/m

Explanation:

(a)

σ = Electrical conductivity = 7.1 x 10⁷ Ω-m⁻¹

d = diameter of the wire = 2.6 mm = 2.6 x 10⁻³ m

Area of cross-section of the wire is given as

A = (0.25) π d²

A = (0.25) (3.14) (2.6 x 10⁻³)²

A = 5.3 x 10⁻⁶ m²

L = length of the wire = 6.7 m

Resistance of the wire is given as

R=\frac{L}{A\sigma }

R=\frac{6.7}{(5.3\times10^{-6})(7.1\times10^{7}) }

R = 0.0178 Ω

(b)

V = potential drop across the ends of wire = 0.060 volts

i = current flowing in the wire

Using ohm's law, current flowing is given as

i = \frac{V}{R}

i = \frac{0.060}{0.0178}

i = 3.4 A

(c)

Current density is given as

J = \frac{i}{A}

J = \frac{3.4}{5.3\times10^{-6}}

J = 6.4 x 10⁵ A/m²

(d)

Magnitude of electric field is given as

E = \frac{J}{\sigma }

E = \frac{6.4 \times 10^{5}}{ 7.1 \times 10^{7}}

E = 9.01 x 10⁻³ V/m

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Answer:

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A solenoid with an air core has a magnetic field pointing along its axis in the positive x direction. This solenoid is then fill
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Answer:

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I did the math.

5 0
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