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Butoxors [25]
2 years ago
6

A standard 1 kilogram weight is a cylinder 51.0 mm in height and 42.0 mm in diameter. Determine the density of the material

Physics
1 answer:
worty [1.4K]2 years ago
3 0

Answer:

14160 kg/m^3

Explanation:

First of all, we need to find the volume of the cylinder.

The volume of the cylinder is given by:

V=\pi r^2 h

where:

r=\frac{d}{2}=\frac{42.0 mm}{2}=21.0 mm=0.021 m is the radius

h=51.0 mm=0.051 m is the height

Substituting, we find

V=\pi (0.021 m)^2 (0.051 m)=7.1 \cdot 10^{-5} m^3

And the density is given by

d=\frac{m}{V}

where m = 1 kg is the mass. Substituting, we find

d=\frac{1 kg}{7.1\cdot 10^{-5} m^3}=14,160 kg/m^3

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Anthony and Maelynn are watching a football game outside on a sunny day. Anthony is wearing a black shirt and Maelynn is wearing
melomori [17]

Answer: Anthony will be warmer after the game.

Explanation :

Anthony and Maelynn are watching a football game outside on a sunny day. Anthony is wearing a black shirt and Maelynn is wearing a white shirt. Anthony will be warmer after the game. The black color is a good absorber of radiation and a bad reflector.

The black color absorbs heat until a thermal equilibrium is attained. So, it is advisable to wear cotton clothes in summers not dark colored clothes.

7 0
2 years ago
Read 2 more answers
The human heart is a powerful and extremely reliable pump. Each day it takes in and discharges about 7500 L of blood. Assume tha
gregori [183]

The answers are:

a) Work=125,923.61J

b) Power=1.46watt

Why?

It seems that you forgot to write the questions of the problem, however, in order to help you, I will try to complete it.

The questions are:

a) How much work does the heart do in a day?

b) What is its power output in watts?

So, solving we have:

We need to convert from liter to cubic meters in order to use the given information, so:

1L=0.001m^{3}\\\\7500L*\frac{0.001m^{3} }{1L}=7.5m^{3}

Also, we need to find the mass given the density of the blood.

1050}\frac{kg}{m^{3}}*7.5m^{3}=7875kg

Now, calculating how much work does the heart do in a day, we have:

Work=Fd=mgh\\\\Work=7875kg*9.81\frac{m}{s^{2}}*1.63m=125,923.61J

Then, calculating what is the power output and its horsepower, we have:

Power=\frac{Work}{time}\\\\Power=\frac{125,923.61J}{86,400s}=1.46watt

Have a nice day!

7 0
2 years ago
Two sinusoidal waves are identical except for their phase. When these two waves travel along the same string, for which phase di
Kamila [148]

Answer:

zero or 2π is maximum

Explanation:

Sine waves can be written

      x₁ = A sin (kx -wt + φ₁)

     x₂ = A sin (kx- wt + φ₂)

When the wave travels in the same direction

      Xt = x₁ + x₂

      Xt = A [sin (kx-wt + φ₁) + sin (kx-wt + φ₂)]

We are going to develop trigonometric functions, let's call

     a = kx + wt

     Xt = A [sin (a + φ₁) + sin (a + φ₂)

We develop breasts of double angles

     sin (a + φ₁) = sin a cos φ₁ + sin φ₁ cos a

    sin (a + φ₂) = sin a cos φ₂ + sin φ₂ cos a

Let's make the sum

     sin (a + φ₁) + sin (a + φ₂) = sin a (cos φ₁ + cos φ₂) + cos a (sin φ₁ + sinφ₂)

to have a maximum of the sine function, the cosine of fi must be maximum

     cos φ₁ + cos φ₂ = 1 +1 = 2

the possible values ​​of each phase are

     φ1 = 0, π, 2π  

     φ2 = 0, π, 2π,  

so that the phase difference of being zero or 2π is maximum

6 0
2 years ago
An ambulance moving at 42 m/s sounds its siren whose frequency is 450 hz. a car is moving in the same direction as the ambulance
Korvikt [17]
(a) Since the ambulance and the car are moving one relative to each other, we have to use the general formula of the Doppler effect, which gives us the shift of the frequency of the siren as heard by an observer in the car:
f'=( \frac{v+v_o}{v+v_s} )f
where
f' is the apparent frequency as heard by the observer in the car
v is the velocity of the wave 
v_o is the velocity of the observer (positive if it is moving towards the source, negative if it is moving away)
v_s is the velocity of the source (positive if the source is moving away from the observer, negative if is is moving towards it)
f is the real frequency of the sound

In the first part of the problem:
v=343 m/s (speed of the sound wave)
v_o =-25 m/s (the car is moving away from the ambulance)
v_s = -42 m/s (the ambulance is moving towards the car)
f=450 Hz (original frequency of the sound)

If we plug the numbers into the formula, we find
f'=( \frac{343 m/s-25 m/s}{343 m/s-42 m/s} )(450 Hz)=475 Hz

b) This time, the ambulance passes the car, so the ambulance is now moving away from the car; this means that v_s must be positive:
v_s=+42 m/s
Moreover, the car is now moving towards the ambulance, so we should reverse also the sign of v_o:
v_o=+25 m/s
All the other data do not change, so if we use the same formula as before, we find
f'=( \frac{343 m/s+25 m/s}{343 m/s+42 m/s} )(450 Hz)=430 Hz
8 0
2 years ago
If the angle of elevation of the cannon is decreased from 35 to 30 degrees, the vertical component of the ball's initial velocit
stealth61 [152]

Answer:

Determine the initial horizontal and vertical velocity for a dart launched with a ... an angle of 30 degrees. Vi=4m/s Vix Vicoso Mas cos 30 = = 30°. Viy=visine ... What is the resultant direction (angle) of the cannon ball (relative to a fixed frame)? ... Which of the following launch angles would result in the greatest time of flight iſ the.

Explanation:

I hope it helped

4 0
1 year ago
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