A bird can fly 25 km/h. How long does it take to fly 15 km?

1 answer:

5 0

25 km/h means that 15 kilometers will be 15/25ths of an hour. Therefore, 3/5 of an hour is 36 minutes, so it would take 36 minutes to fly that distance.

You might be interested in

Which, if any, of the following statements concerning the work done by a conservative force is NOT true? All of these statements

masya89 [10]

Answer:

When the starting and ending points are the same, the total work is zero.

Explanation:

option ( D )correct

A force is said to be conservative when the work done by the force in moving a particle from a point A to a point B is independent of the path followed between A and B and is the same for all the paths. The work done depends only on the particles initial and final positions. And when the initial and final position in conservative field are same the work done is said to be zero.

8 0

2 years ago

A brick is resting on a rough incline as shown in the figure. The friction force acting on the brick, along the incline, is

Tasya [4]

B) equal to the gravitational force of the brick

6 0

2 years ago

Read 2 more answers

A bullet blasts from the barrel of a gun upward in the vertical direction with an initial speed of 700 m/s . Find the maximum al

ryzh [129]

The maximum altitude that the bullet will reach is the point at which its velocity is zero. The equation that may be used in order to determine the altitude is,

D = ((Vi)2 – (Vf)2)/2g

Where Vi and Vf are the initial and final velocities, respectively. g is the deceleration due to gravity.

Substituting the known values,

D = ((700 m/s)2 – (0 m/s)2) / (2(-9.8 m/s2))

D = 25000 m

Thus, the maximum height is 25000 m.

For the time needed to reach it, we use the equation,

Vf = Vi – (g)(t)

Substituting,

0 = 700 m/s – (-9.8 m/s2)(t)

The value of t is equal to 71.43 s.

6 0

2 years ago

A trebuchet was a hurling machine built to attack the walls of a castle under siege. A large stone could be hurled against a wal

Studentka2010 [4]

(a) 18.9 m/s

The motion of the stone consists of two independent motions:

- A horizontal motion at constant speed

- A vertical motion with constant acceleration ( $g=9.8 m/s^2$ ) downward

We can calculate the components of the initial velocity of the stone as it is launched from the ground:

$u_x = v_0 cos \theta = (25.0)(cos 41.0^{\circ})=18.9 m/s\\u_y = v_0 sin \theta = (25.0)(sin 41.0^{\circ})=16.4 m/s$

The horizontal velocity remains constant, while the vertical velocity changes due to the acceleration along the vertical direction.

When the stone reaches the top of its parabolic path, the vertical velocity has became zero (because it is changing direction): so the speed of the stone is simply equal to the horizontal velocity, therefore

$v=18.9 m/s$