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Gnoma [55]
2 years ago
15

A bullet blasts from the barrel of a gun upward in the vertical direction with an initial speed of 700 m/s . Find the maximum al

titude reached by this bullet and the time needed to reach it
Physics
1 answer:
ryzh [129]2 years ago
6 0

The maximum altitude that the bullet will reach is the point at which its velocity is zero. The equation that may be used in order to determine the altitude is,

<span>                                   D = ((Vi)2 – (Vf)2)/2g</span>

Where Vi and Vf are the initial and final velocities, respectively. g is the deceleration due to gravity.

Substituting the known values,

<span>                                    D = ((700 m/s)2 – (0 m/s)2) / (2(-9.8 m/s2))</span>

<span>                                    D = 25000 m</span>

 

Thus, the maximum height is 25000 m.

 

For the time needed to reach it, we use the equation,

<span>                                    Vf = Vi – (g)(t)</span>

Substituting,

<span>                                    0 = 700 m/s – (-9.8 m/s2)(t)</span>

The value of t is equal to 71.43 s.

<span> </span>

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2.5m/s

Explanation:

Given parameters:

Initial velocity = 0m/s

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time of travel = 5s

Solution:

Final velocity = ?

Solution:

Acceleration can be defined as the change in velocity with time:

          Acceleration = \frac{Final velocity - Initial velocity}{time}

  From the equation above, the unknown is final velocity:

Final velocity - initial velocity = Acceleration x time

 since initial velocity = 0

   Final velocity = 0.5 x 5 = 2.5m/s

Learn more:

Acceleration brainly.com/question/3820012

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6 0
2 years ago
The point on the graph that lies on the y-axis (vertical axis) is called the y-intercept. What does the y-intercept tell you abo
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Answer:

The starting position of the runner.

Explanation:

When you look at the graph, you can see that the first point on the graph is twenty on the y-axis.

The runner starts at twenty, and ends at thirty.

Therefore, the runner starts at twenty on the y-axis, so it's the starting position of the runner.

7 0
2 years ago
A charge of 4.9 x 10-11 C is to be stored on each plate of a parallel-plate capacitor having an area of 150 mm2 and a plate sepa
Triss [41]

Answer:2.53*10^-10F

Explanation:

C=£o£r*A/d

Where £ is the permitivity of a constant

£o= 8.85*10^-12f/m

£r=6.3

A=150mm^2=0.015m^2

d=3.3mm= 0.0033m

C=8.85*10^-12*6.3*0.015/0.0033

C=8.85*6.3*10^-12*0.015/0.0033

C=55.755*0.015^-12/0.003

C=8.36/3.3*10^-13+3

C=2.53*10^-10F

7 0
2 years ago
A force of 150 N accelerates a 25 kg wooden chair across a wood floor at 4.3 m/s2 . How big is the frictional force on the block
solniwko [45]
We can first calculate the net force using the given information.

By Newton's second law, F(net) = ma:

F(net) = 25 * 4.3 = 107.5

We can now calculate the frictional force, f, which is working against the applied force, F(app) (this is why the net force is a bit lower):

f = F(net) - F(app) = 150 - 107.5 = 42.5 N

Now we can calculate the coefficient of friction, u, using the normal force, F(N):

f = uF(n) --> u = f/F(N)
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4 0
2 years ago
A rock is rolling down a hill. At position 1, it’s velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, it’s velo
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Answer

Hi,

correct answer is {D} 3.5 m/s²

Explanation

Acceleration is the rate of change of velocity with time. Acceleration can occur when a moving body is speeding up, slowing down or changing direction.

Acceleration is calculated by the equation =change in velocity/change in time

a= {velocity final-velocity initial}/(change in time)

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The units for acceleration is meters per second square m/s²

In this example, initial velocity =2.0m/s⇒u

Final velocity=44.0m/s⇒v

Time taken for change in velocity=12 s⇒Δt

a= (44-2)/12  = 42/12

3.5 m/s²

Best Wishes!

5 0
2 years ago
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