two people, each with a mass of 70 kg, are wearing inline skates and are holding opposite ends of a 15m rope. One person pulls f
1 answer:
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Answer:
7.9 m/s
Explanation:
When both balls collide, they have spent the same time for their motions.
Motion of steel ball
This is purely under gravity. It is vertical.
Initial velocity, <em>u </em>= 0 m/s
Distance, <em>s</em> = 4.0 m - 1.2 m = 2.8 m
Acceleration, <em>a</em> = g
Using the equation of motion
Motion of plastic ball
This has two components: a vertical and a horizontal.
The vertical motion is under gravity.
Considering the vertical motion,
Initial velocity, <em>u </em>= ?
Distance, <em>s</em> = 1.2 m
Acceleration, <em>a</em> = -<em>g </em> (It is going up)
Using the equation of motion
Substituting the value of <em>t</em> from the previous equation,
Taking <em>g</em> = 9.8 m/s²,
This is the vertical component of the initial velocity
Considering the horizontal motion which is not accelerated,
horizontal component of the initial velocity is horizontal distance ÷ time.
The initial velocity is
Answer:
Check the explanation
Explanation:
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
The image is virtual
The image is upright
given
R = 1.5 cm
object distance, u = 1.1 cm
focal length of the ball, f = -R/2
= -1.5/2
= -0.75 cm
let v is the image distance
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(1.1)
v = -0.446 cm <<<<<---------------Answer
magnification, m = -v/u
= -(-0.446)/1.1
= 0.405 <<<<<<<<<---------------Answer
Kindly check the diagram in the attached image below.
