Answer:
The magnitude of the acceleration of the car is 35.53 m/s²
Explanation:
Given;
acceleration of the truck, 
= 12.7 m/s²
mass of the truck, 
= 2490 kg
mass of the car, 
= 890 kg
let the acceleration of the car at the moment they collided = 
Apply Newton's third law of motion;
Magnitude of force exerted by the truck = Magnitude of force exerted by the car.
The force exerted by the car occurs in the opposite direction.
Therefore, the magnitude of the acceleration of the car is 35.53 m/s²
Answer:
D
Explanation:
Speed = distance / time
her time for the first journey = 20 miles / 60 miles/hr = 1/3 hr
her time for second part of the journey = her remaining distance / her speed = (80 - 20) miles / 30 miles/hr = 60 miles / 30 miles/hr = 2 hrs
total time spend by her = 2 hr+ 1/3 hr = 2 1/3 hrs
her traveling the distance at 40 miles per hour = 80 miles / 40 miles /hr = 2 hrs
the time less she would drive if she drive the entire distance at 40 miles/hr = 2 1/3 hrs - 2 hrs = 1/3 hr
Answer: The power is 156 watt
Explanation:
is in the attachment
Answer:
Option A; ITS SURFACE IS COOLER THAN THE SURFACE OF THE SUN.
Explanation:
A red supergiant star is a larger and brighter type of red giant star. Red supergiants are often variable stars and are between 200 to 2,000 times bigger than the Sun. Example is Betelgeuse.
Betelgeuse is one of the largest known stars, it has a diameter of about 700 times the size of the Sun or 600 million miles, it emits almost 7,500 times as much energy as the Sun, it has a rather low surface temperature (6000F compared to the Sun's 10,000F); this means that it has a more cooler surface than the Sun's surface.
This low temperature also means that the star will appear orange-red in color, and the combination of size and temperature makes it a kind of star called a red super giant.
Although, all the statements above are correct, the only one that can be inferred from the red color of Betelgeuse is that ITS SURFACE IS COOLER THAN THE SURFACE OF THE SUN.
Answer:
P = 216 Watts
Explanation:
Given that,
Resistance 1, 
Resistance 2, 
Voltage, V = 36 V
We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.
Firstly, lets find current of the 6 ohms resistor such that,
V = IR
The power dissipated by 6 ohms resistor is given by :
So, the power dissipated across 6 ohm resistor is 126 watts.
