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____ [38]
2 years ago
6

Which of the following statements is false?

Physics
2 answers:
agasfer [191]2 years ago
6 0

A & B

Observe the path of the light ray as it passes through the lenses as shown in the attached images. Concave lenses diverge light rays while the convex lens converges the light rays.

Explanation:

Real images are formed where the rays converge, a property of images by convex lenses. Convex lenses can be used to magnify objects. If the image occurs before the focal point of the lens then the image will be upright but smaller. The images inverts and gets bigger past the focal point.

Virtual images are property of concave lenses. These images appear closer but smaller than the real object.

Learn More:

For more on images formed by lenses check out;

brainly.com/question/6722295

brainly.com/question/12191285

brainly.com/question/12529812

brainly.com/question/11788630

#LearnWithBrainly

N76 [4]2 years ago
4 0

Answer:

C. Convex lenses always produce images that are inverted.

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An electrical conductor is an element with __________ electrons in its outer orbit.
Setler [38]
An electric conductor is an element with free electrons in its outer orbit
5 0
2 years ago
High-speed stroboscopic photographs show that the head of a 200 g golf club is traveling at 43.7 m/s just before it strikes a 45
Helga [31]

Answer:

41.27m/s

Explanation:

According to law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the velocity after impact

Given

m1 = 0.2kg

u1 = 43.7m/s

m2 = 45.9g = 0.0459kg

u2 = 30.7m/s

Required

Velocity after impact v

Substitute the given parameters into the formula

0.2(43.7)+0.0459(30.7) = (0.2+0.0459)v

8.74+1.409 = 0.2459v

10.149 = 0.2459v

v = 10.149/0.2459

v = 41.27m/s

Hence the speed of the golf ball immediately after impact is 41.27m/s

8 0
2 years ago
A 0.900 kg ornament is hanging by a 1.50 m wire when the ornament is suddenly hit by a 0.400 kg missile traveling horizontally a
just olya [345]

Explanation:

The given data is as follows.

  Mass of the ornament (m_{1}) = 0.9 kg

  Length of the wire (l) = 1.5 m

 Mass of missile (m_{2}) = 0.4 kg

 Initial speed of missile (u_{2}) = 12 m/s

         r = 1.5 m

According to the law of conservation of momentum,

                   p_{i} = p_{f}  

     m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v

Putting the given values into the above formula as follows.

          m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v

         0.9 \times 0 + 0.4 \times 12 = (0.9 + 0.4)v

              0 + 4.8 = 1.3v

                  v = 3.69 m/s

Now, the centrifugal force produced is calculated as follows.

            F_{c} = (m_{1} + m_{2}) \times \frac{v^{2}}{r}

                       = (0.9 + 0.4) \times \frac{(3.69)^{2}}{1.5}

                       = 11.80 N

Hence, tension in the wire is calculated as follows.

              T = F_{c} + (m_{1} + m_{2})g

                 = 11.80 N + (0.9 + 0.4) \times 9.8

                 = 24.54 N

Thus, we can conclude that tension in the wire immediately after the collision is 24.54 N.

4 0
2 years ago
What is the instantaneous velocity v of the particle at t=10.0s?
Alexeev081 [22]

Instantaneous velocity is defined at a specific value of time t. It can never be observed or measure. To know a velocity, one must know its distance and velocity. It is represented by the equation velocity is equal to delta distance over delta time. The problem above lacks data.

8 0
2 years ago
the mass of piece of granite is 15.6g when it is suspended can a mass of 5.5g of water is displaced find the dencity of granite
Blababa [14]

Answer:

2836.36 kg/m³

Explanation:

Applying,

Densty of granite(D')/Density of water(D) = weight of granite(W')/weight of water displaced(W)

D'/D = W'/W................... Equation 1

Make D' the subject of the equation

D' = W'D/W............... Equation 2.

From the question,

Given: W' = mg = 9.8(15.6/1000) = 0.15288 N, W = 9.8(5.5/1000) = 0.0539 N, Constant: D = 1000 kg/m³

Substitute these values into equation 2

D' = 1000(0.15288)/0.0539

D' = 2836.36 kg/m³

3 0
1 year ago
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