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2 years ago

Which of the following statements is false?

Physics

2 answers:

agasfer [191]2 years ago

6 0

A & B

Observe the path of the light ray as it passes through the lenses as shown in the attached images. Concave lenses diverge light rays while the convex lens converges the light rays.

Explanation:

Real images are formed where the rays converge, a property of images by convex lenses. Convex lenses can be used to magnify objects. If the image occurs before the focal point of the lens then the image will be upright but smaller. The images inverts and gets bigger past the focal point.

Virtual images are property of concave lenses. These images appear closer but smaller than the real object.

Learn More:

For more on images formed by lenses check out;

brainly.com/question/6722295

brainly.com/question/12191285

brainly.com/question/12529812

brainly.com/question/11788630

#LearnWithBrainly

N76 [4]2 years ago

4 0

Answer:

C. Convex lenses always produce images that are inverted.

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On a snowy day, when the coefficient of friction μs between a car’s tires and the road is 0.50, the maximum speed that the car c

Nana76 [90]

Answer:

28.1 mph

Explanation:

The force of friction acting on the car provides the centripetal force that keeps the car in circular motion around the curve, so we can write:

$F=\mu mg = m \frac{v^2}{r}$ (1)

where

$\mu$ is the coefficient of friction

m is the mass of the car

g = 9.8 m/s^2 is the acceleration due to gravity

v is the maximum speed of the car

r is the radius of the trajectory

On the snowy day,

$\mu=0.50\\v = 20 mph = 8.9 m/s$

So the radius of the curve is

$r=\frac{v^2}{\mu g}=\frac{(8.9)^2}{(0.50)(9.8)}=16.1 m$

Now we can use this value and re-arrange again the eq. (1) to find the maximum speed of the car on a sunny day, when $\mu=1.0$ . We find:

$v=\sqrt{\mu g r}=\sqrt{(1.0)(9.8)(8.9)}=12.6 m/s=28.1 mph$

7 0

1 year ago

Read 2 more answers

The magnetic field around a current-carrying wire is ________proportional to the current and _________proportional to the distan

PSYCHO15rus [73]

Answer:Thus, The magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire. If the current triples while the distance doubles, the strength of the magnetic field increases by one and half (1.5) times.

Explanation:

Magnetic field around a long current carrying wire is given by

$B=\frac{\mu _o I}{2\pi r}$

where B= magnetic field

$\mu _o=$ permeability of free space

I= current in the long wire and

r= distance from the current carrying wire

Thus, The magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.

Now if I'=3I and r'=2r then magnetic field B' is given by

$B'=\frac{\mu _oI'}{2\pi r'}=\frac{\mu _o3I}{2\pi 2r}=1.5B$