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#1
Volume of lead = 100 cm^3
density of lead = 11.34 g/cm^3
mass of the lead piece = density * volume
so its weight in air will be given as
now the buoyant force on the lead is given by
now as we know that
so by solving it we got
V = 11.22 cm^3
(ii) this volume of water will weigh same as the buoyant force so it is 0.11 N
(iii) Buoyant force = 0.11 N
(iv)since the density of lead block is more than density of water so it will sink inside the water
#2
buoyant force on the lead block is balancing the weight of it
(ii) So this volume of mercury will weigh same as buoyant force and since block is floating here inside mercury so it is same as its weight = 11.11 N
(iii) Buoyant force = 11.11 N
(iv) since the density of lead is less than the density of mercury so it will float inside mercury
#3
Yes, if object density is less than the density of liquid then it will float otherwise it will sink inside the liquid
Answer:
a=
Explanation:
The net force, of the box is expressed as a product of acceleration and mass hence
where m is mass and a is acceleration
Making a the subject, a=
From the attached sketch,
∑ where
is frictional force and
is horizontal angle
Substituting ∑ as
in the equation where we made a the subject
a=
Since we’re given the value of F as 240N, as 41.5N,
as
and mass m as 30kg
a=
