Answer:
man upward acceleration is 0.14m/s^2
Explanation:
given data:
mass of man = 72 kg
downward force = 360 N
The mass of man of weight 72 kg is hang from two sections of rope, one section pf rope ties around man waist and other section is ties in man hands. when he pulls down the rope with 360 N force then each section of rope pulls with 360 N
we know that
Weight= mass × gravity= 72kg × 9.8 = 705.6N
Force = mass× acceleration
Force= -705.6 + (2 × 358) = 10.4 N
In collision type of problems since momentum is always conserved
we can say
So here along with this equation we also required one more equation for the restitution coefficient
so above two equations are required to find the velocity after collision
here the change in velocity occurs due to the contact force while they contact in each other
so this is the impulse of collision while they are in contact with each other while in collision which changes the velocity of two colliding objects
Answer:
The radius of the curve that Car 2 travels on is 380 meters.
Explanation:
Speed of car 1,
Radius of the circular arc,
Car 2 has twice the speed of Car 1,
We need to find the radius of the curve that Car 2 travels on have to be in order for both cars to have the same centripetal acceleration. We know that the centripetal acceleration is given by :
According to given condition,
On solving we get :
So, the radius of the curve that Car 2 travels on is 380 meters. Hence, this is the required solution.
Answer:
The rate of change of the height is - 4 ft/s
Solution:
As per the question:
Height of the person, y = 5 ft
The rate at which the person walks away,
Distance of the spotlight from the wall, x = 40 ft
Now,
To calculate the rate of change in the height, of the person when, x = 10 m:
From fig 1.
xy = 200 (1)
Differentiating the above eqn w.r.t time t:
Thus
(2)
From eqn (1):
When x = 10 ft
10y = 200
y = 20 ft
Using eqn (2):
