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sineoko [7]
2 years ago
7

In a harbor, you can see sea waves traveling around the edges of small stationary boats. Why does this happen?

Physics
1 answer:
faust18 [17]2 years ago
8 0
Below are the choices that can be found in the other sources:

A. diffraction 
<span>B. refraction </span>
<span>C. reflection </span>
<span>D. transmission
</span>
The answer is diffraction. It means that <span>the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.</span>
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A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i
oksian1 [2.3K]
Acceleration, in physics, is the rate of change of velocity of an object with respect to time. <span> Anytime an object's velocity is changing, the object is said to be </span><span>accelerating. It can be calculated as follows:

acceleration = 8.2 - 3.5 / 1.5 = 3.1 m/s</span>²

Hope this answers the question.
5 0
2 years ago
Read 2 more answers
Q 32.35: The isotope 235U decays by alpha emission with a half-life of 7.0 x 108 y. It also decays (rarely) by spontaneous fissi
Julli [10]

Answer:

rate of fission =5.89*10^3 1\Year

Explanation:

we know that

rate of fission is given asrate of fission = \frac{0.69}{(T_{1/2})_{fission}} *\frac{ Mass* Avogardo\ number}{Molar\ mass}

(T_{1/2})_{fission} = 3*10^{17} y

mass = 1.0 g

avogardo number = 6.02*10^23

molar mass of isotopes 235U =235

Putting all value to get rate of emission

rate of fission = \frac{0.69}{3*10^{17}} *\frac{1.0*6.02*10^{23}}{235}

rate of fission =5.89*10^3 1\Year

5 0
2 years ago
A physics student stands on the rim of the canyon and drops a rock. The student measures the time for it to reach the bottom to
madam [21]

Answer:

Canyon is 50.176 meter deep.

Explanation:

The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.

Given data:

Time = t = 3.2 s

Initial velocity = v_{i} = 0 m/s

Gravitational acceleration = g = 9.8 m/s²

Height = h = ?

According to second equation of motion

h = v_{i}t + \frac{1}{2}gt^{2}

As initial velocity is zero, So the first term of right hand side of above equation equal to zero

h = \frac{1}{2}gt^{2}

h = (0.5)(9.8)(3.2)²

h = 50.176 m

This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.

5 0
2 years ago
Three wires are made of copper having circular cross sections. Wire 1 has a length l and radius r. Wire 2 has a length l and rad
Alex73 [517]

Explanation:

Below is an attachment containing the solution.

4 0
2 years ago
The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u
Aleksandr [31]
Let
upthrust = T
weight = W = mg
Air resistance = F

When balloon is descending, air resistance acts upwards (positive)
By Newton's first law, the net force on the balloon is zero, or
T+F-W=0......................(1)

Let w=weight of material dumped so that balloon now travels upwards at constant speed.
Air resistance acts against motion, namely downwards.
The Newton's equation now reads
T-F-(W-w)=0................(2)

Subtract (2) from (1)
T+F-W - (T-F-(W-w)) = 0
Solve for w
w=2F, or
the WEIGHT of material to be released equals twice the resistance of air.
3 0
2 years ago
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