Answer:
the new diameter of the third ring = 0.607 mm
Explanation:
Consider the radius of 
bright ring when air is in between the lens and the plate ;
Using the expression: 
for the radius of the bright ring since the liquid (water ) of the refractive index 'n' is now in between the lens and the plate;
where;
= number of fringe
λ = wavelength
R = radius
n = refractive index of water
Now ;
the radius r of the third bright ring when the air is in between lens and plate = 
The new radius of the third bright fringe is 
Calculating the new diameter ; we have:
d(3) = 2(r(3))
d(3) = 2(0.3035)
d = 0.607 mm
Thus, the new diameter of the third ring = 0.607 mm
U = 0, initial vertical velocity
Neglect air resistance, and g = 9.8 m/s².
The time, t, required for the pen to attain a vertical velocity of 19.62 m/s is given by
19.62 m/s = 0 + (9.8 m/s²)*(t s)
t = 19.62/9.8 = 2.00 s
Answer: 2.0 s
Answer:
The magnitude of the velocity of the aircraft P relative to aircraft Q is zero
Explanation:
The velocity of the two aircraft, P & Q, v = 300 m/s
The angle of the direction between them, Ф = 90°
The magnitude of the velocity of aircraft P relative to aircraft Q is given by the formula
<em> V = v cos Ф
</em>
Substituting the values in the above equation
v = 300 x cos 90°
= 300 x 0
= 0
Since the aircraft are at right angles, the velocity of one aircraft relative to the other is zero.
Ceres: Yes!
Namaka: No!
Eris: Yes!
Charon: No. (it's a satellite, and dwarf planet's can't be satellites!)
Haumea: Yes!
Makemake: Yes!
Pluto: Yes!
Glad To Help;)
Newtons second law.. <span>The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.</span>
