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lord [1]
2 years ago
7

550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c

ompress the gas by a factor of 11.0, starting from its initial volume?
Physics
1 answer:
Over [174]2 years ago
7 0

Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

Explanation:

The given variables are

Work done = 550 J

Volume change = V₂ - V₁ = -0.5V₁

Thus the product of pressure and volume change = work done by gas, thus

P × -0.5V₁ = 500 J

Hence -PV₁ = 1000 J

also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore  P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂

Also to compress the gas by a factor of 11 we have

P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11  = 909.091 J of work

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A solar heated house loses about 5.4 × 107 cal through its outer surfaces on a typical 24-h winter day.
mojhsa [17]

Answer:

C

Explanation:

Q=mcΔθ

Q=quantity of heat   , m= mass of the storage rock

Δθ= temperature change.

m= Q/(cΔθ)

Q=5.410^{7}

Δθ=62°C-20°C

 =42°C

c=0.21cal/g.°C

m=\frac{5.4*10^{7} }{0.21*42} \\\\m=6122448.98g\\

m≈6100000g

m≈6100kg

4 0
2 years ago
Two objects exert a gravitational force on 8 N on one another. What would that force be if the mass of BOTH objects were doubled
seropon [69]
<span>Based on Newton's law of universal gravitation, the equation for the gravitational force exerted by an object on another object is given by:
F = Gm1m2/(r^2)
where G is the universal gravitational constant, F is the gravitational force exerted, m1 is the mass of the first object, m2 is the mass of the second object, and r is the separation distance between the two objects.
If the mass of both objects were doubled, then we would have: m1' * m2' = (2m1) * (2m2) = 4m1m2. Assuming r stays constant (G is a constant so that won't change anyway), then this means that the new force will be 4 times greater, ie 8N * 4 = 32N of gravitational force. </span>
4 0
2 years ago
Whipple is confused about the connection between the velocity and acceleration of the tennis ball. he decides to compare the vel
tamaranim1 [39]

The speed of the ball is always zero and the acceleration is always -g when it reaches the top of its motion. This is because when the ball is free, only gravity acts on it which is always downwards, hence g is the net acceleration and it is always negative. However the velocity does not direction change instantly, negative acceleration first slows down the ball with a positive velocity, until that point the ball keeps moving up, then the ball velocity becomes zero just before changing direction and becoming negative after which the ball will now go down along gravity. Hence the ball velocity is zero at the top (neither going up nor down). Mathematically this can be seen as velocity is the integration of acceleration.

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The bottom of the inner curve of a hook is called
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Slip hook or blunt hook
8 0
2 years ago
A positive point charge Q is fixed on a very large horizontal frictionless tabletop. A second positive point charge q is release
andrezito [222]

Explanation:

A positive point charge Q is fixed on a very large horizontal friction less tabletop. A second positive point charge q is released from rest near the stationary charge and is free to move.

As per the law of conservation of energy the change in kinetic energy is equal to the change in potential energy.

The mathematical expression for the conservation of energy is given by :

\dfrac{1}{2}mv^2=-k\dfrac{q_1q_2}{r_2^2}-(-k\dfrac{q_1q_2}{r_1^2})

On solving the above equation, we get the value of v as :

v=\sqrt{\dfrac{2kq_1q_2}{m}(\dfrac{1}{r_1^2}-\dfrac{1}{r_2^2})}

In the above expression, as the term (\dfrac{1}{r_1^2}-\dfrac{1}{r_2^2}) increase, as r_2 increases, the value of \dfrac{1}{r_2} decreases. So, the correct option is (B) "As it moves farther and farther from Q, its speed will increase".

4 0
2 years ago
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