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lord [1]
1 year ago
7

550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c

ompress the gas by a factor of 11.0, starting from its initial volume?
Physics
1 answer:
Over [174]1 year ago
7 0

Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

Explanation:

The given variables are

Work done = 550 J

Volume change = V₂ - V₁ = -0.5V₁

Thus the product of pressure and volume change = work done by gas, thus

P × -0.5V₁ = 500 J

Hence -PV₁ = 1000 J

also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore  P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂

Also to compress the gas by a factor of 11 we have

P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11  = 909.091 J of work

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Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink?
bearhunter [10]

Answer:

It will sink

Explanation:

An object in the water can float only if its density is lower than the density of the water.

In fact, for an object completely immersed in water, there are two forces acting on it:

- Its weight, W=mg=\rho_o V g, downward, where \rho_o is the density of the object, V its volume and g the gravitational acceleration

- The buoyant force, B=\rho_w V g, upwards, there \rho_w is the density of the water

We see that when the density of an object is larger than the density of the water, \rho_o > \rho_w, the weight is greater than the buoyant force, W>B, so the object sinks.

In this case, the rock has a density of 1.73 g/cm3, while water has a density of 1.0 g/cm^3, so the rock will sink.


5 0
2 years ago
Read 2 more answers
Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8
Tema [17]

Answer:

The value of developed electric force is 3.516\times 10^{- 7} N

Solution:

As per the question:

Mass of the droplet = 1.8 mg = 1.8\times 10^{- 6} kg

Charge on droplet, Q = 25 pC = 25\times 10^{- 12} C

Distance between the 2 droplets, D = 0.40 cm = 0.004 m

Now, the Electrostatic force given by Coulomb:

F_{E} = \frac{1}{4\pi epsilon_{o}}.\frac{Q^{2}}{D^{2}}

\frac{1}{4\pi epsilon_{o}} = 9\times 10^{9} m/F

F_{E} = (9\times 10^{9}).\frac{(25\times 10^{- 12})^{2}}{0.004^{2}}

F_{E} = 3.516\times 10^{- 7} N

The magnitude of force is too low to be noticed.

8 0
1 year ago
Read 2 more answers
__________ curves help lessen the effect of the force of the forward motion on your vehicle as it enters the curve.
Rainbow [258]

Answer:

Banked

Explanation:

Banked curves are formed when the inner edge is below the outer edge.

It is done in order to ensure the reliability of the frictional force as it varies when the road is wet wet or oily. Thus in order to avoid these problems the curved roads are banked.

Banking of the curve provides the necessary centripetal force, i.e., the horizontal component of the normal reaction force to keep the vehicle i motion and thus helps in reducing the effect of the forward motion force on the vehicle.

5 0
1 year ago
Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30 m. The electric field at a point P, which
krok68 [10]

Answer:

E_{max}=41666.66\ N/C

Explanation:

Given that,

The radius of sphere, r = 0.3 m

Distance from the center of the sphere to the point P, x = 0.5 m

Electric field at point P, E_P=15000\ N/C (radially outward)

The maximum electric field is at the surface of the sphere. We know that the electric field is inversely proportional to the distance. So,

\dfrac{E_{max}}{E_p}=\dfrac{0.5^2}{0.3^2}

\dfrac{E_{max}}{15000}=\dfrac{0.5^2}{0.3^2}

{E_{max}}=\dfrac{0.5^2}{0.3^2}\times 15000

E_{max}=41666.66\ N/C

So, the magnitude of the electric field due to this sphere is 41666.66 N/C. Hence, this is the required solution.

6 0
1 year ago
An artificial satellite in a low orbit circles the earth every 98 minutes. what is its angular speed in rad/s?
postnew [5]
To finish one orbit it will take 98 x 60 seconds. So; <span>(2 x pi)/(98 x 60) = 1.07 x 10^-3 rad/sec. </span><span>
</span>
8 0
2 years ago
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