acceleration of rocket is given here as
now we know that
now integrating both sides
here since its given that rocket will accelerate for t = 10 s
so here we have
so after t = 10 s the speed of rocket will be 130 m/s upwards
We know that every object exerts an attraction on every other object and the heavier the object ___ the attraction.
1 answer:
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Answer:
This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap
Explanation:
We must work on this problem using the rotational equilibrium equations and then they compared the tension values that the cable supports.
Let's start with fixing a reference system on the hinge of the flag, we take as positive the anti-clockwise turn
They indicate the weight of the pole W₁ = 120 lb and a length of L = 9 ft, the weight of the man W₂ = 150, we assume that the cable is at the tip of the pole
- L + W₂ L + W₁ L / 2 = 0
T_{y} = W₂ + W₁ / 2
T_{y} = 120 + 150/2
T_{y} = 195 lb
we use trigonometry to find the cable tension
sin 30 = T_{y} / T
T = T_{y} / sin 30
T = 195 / sin 30
T = 390 lb
This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap
T < 500 lb
Answer:
See the explanation below.
Explanation:
12) When an object is falling, how does the objects velocity change? what formula do you use?
The speed of a falling object is increased by a value of 9.81 meters per second per second. That is if we throw any body regardless of mass from a considerable height, its speed in the first second will be 9.81[ m/ s] , in the next second will be equal to 19.62 [m/s] in the next will be equal to 29.43 [m/ s].
The formula is:
where:
vo = initial velocity = 0
g = gravity = 9.81[m/s^2]
t = time [s]
13)
what is a falling speed at 6s, 9s, 112s?
v = 0 + (9.81*6) = 58.86[m/s]
v = 0 + (9.81*9) = 88.29 [m/s]
v = 0 + (9*112) = 1098.72 [m/s]
14)
If an object is falling at 65 [m/s]. How long has it been falling ? what is the formula that you use?
The formula is the same:
65 = 0 + 9.81*t
t = 65/9.81
t = 6.62[s]
15)
What formula is used to determine the distance an object is falling ?
where:
y = distance [m]
yo = initial distance, in most of the cases and depending of the reference point it will be eqaul to zero
vo = initial velocity, if it is free fall, then = 0
t = time [s]
g = gravity = 9.81[m/s^2]
This equation will be reduce to:
16)
using the times given in problem 13. Determine the distance fallen for each.
y = 0.5*9,81*(6)^2 = 176.58 [m]
y = 0.5*9,81*(9)^2 = 397.3 [m]
y = 0.5*9,81*(112)^2 = 61528.3 [m]
17)
If an object has fallen a distance of 87.3 [m]. How long was it falling?
87.3 = 0.5*9.81*t^2
Answer:
a) The sign of the charge is positive.
b) The magnetic force on the particle is 0.050 newtons.
Explanation:
The magnetic force F on a moving charge with velocity v passing through a magnetic field B is:
(1)
a)
Because it is a cross product, we can find the direction of the force using the right-hand rule, that is too the direction of the movement. We have two possibilities here because the velocity vector and magnetic field are perpendicular: the particle deflects towards east or toward west, which depends on the charge of the particle. Note that if you put your right hand fingers, except thumb, pointing towards north (direction of velocity) and later close them in the direction of the magnetic field, if you maintain your thumb perpendicular to this movement it will point towards east (See figure), so that will be de direction of the force if the charge is positive, but if the charge is negative, the direction will be opposite (towards west). So the charge has to be positive to deflects towards east.
b)
Now by 1:
