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rodikova [14]
2 years ago
15

An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch

arge density σ = -0.35 μC/m2. A thin wire, with linear charge density λ = 1.1 μC/m, is inserted along the shells' axis. The shell and the wire do not touch and these is no charge exchanged between them.a) What is the new surface charge density, in microcoulombs per square meter, on the inner surface of the cylindrical shell?b) What is the new surface charge density, in microcoulombs per square meter, on the outer surface of the cylindrical shell?c) Enter an expression for the magnitude of the electric field ou

Physics
1 answer:
gayaneshka [121]2 years ago
8 0

Answer:

Explanation:

Solution is in the picture attached

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According to the diagram, in order for a solar eclipse to occur, the Earth, Moon, and Sun must A) form a right angle with the Mo
torisob [31]

Answer:

B) form a straight line with the Moon in the middle.

Explanation:

  • For the occurrence of a solar eclipse the earth and the moon and the sun must be in a straight line and moon should be in center of the earth so that it completely blocks the rays of the sun and the shadow falls on earth and the sun appears to form a ring and thus the eclipse takes place.
7 0
2 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745 ra
skelet666 [1.2K]

Answer:

So the acceleration of the child will be 8.05m/sec^2

Explanation:

We have given angular speed of the child \omega =1.25rad/sec

Radius r = 4.65 m

Angular acceleration \alpha =0.745rad/sec^2

We know that linear velocity is given by v=\omega r=1.25\times 4.65=5.815m/sec

We know that radial acceleration is given by a=\frac{v^2}{r}=\frac{5.815^2}{4.65}=7.2718m/sec^2

Tangential acceleration is given by

a_t=\alpha r=0.745\times 4.65=3.464m/sec^

So total acceleration will be a=\sqrt{7.2718^2+3.464^2}=8.05m/sec^2

7 0
2 years ago
A 4-N object object swings on the end of a string as a simple pendulum. At the bottom of the swing, the tension in the string is
Amanda [17]

Answer:

Explanation:

Given mg = 4N .

m = 4 / g

At the bottom of the swing let centripetal acceleration be a

T - mg = ma

9 - 4 = ma

5 = 4 a  / g

a =  5g / 4

6 0
2 years ago
Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. Wha
MArishka [77]

Answer:

P = 1.64 \times 10^4 Watt

Explanation:

Here we know that the glider is accelerated uniformly from rest to final speed of 25.7 m/s in total distance of d = 46.9 m

so we will have

v_f = 25.7 m/s

v_i = 0

d = 46.9

so for uniformly accelerated motion we have

d = \frac{v_f + v_i}{2} t

46.9 = \frac{25.7 + 0}{2}t

t = 3.65 s

now we will find the total work done given as change in kinetic energy

W = \frac{1}{2}mv^2

W = \frac{1}{2}(181)(25.7^2)

W = 5.97 \times 10^4 J

now power is given as

P = \frac{W}{t}

P = \frac{5.97 \times 10^4}{3.65}

P = 1.64 \times 10^4 Watt

6 0
2 years ago
Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal,
VARVARA [1.3K]

Answer: yes.

Explanation: The light that will be incidented on that metal is visible light.

It depends on 3 factors:

1. The temperature

2. The specific heat capacity of the metal

3. The thermal conductivity of the metal.

The metal getting warmer also depend on the reflection and the absorption of light energy in which it will surely absorb some energy and not reflect all.

When visible light is absorbed by an object, the object converts the short wavelength light into long wavelength heat. This causes the object to get warmer. 

6 0
2 years ago
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