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mrs_skeptik [129]
1 year ago
15

A car travels at a constant rate for 25 miles, going due east for one hour. Then it travels at a constant rate another 60 miles

east for one hour. What is the instantaneous velocity at any time during the second hour of the trip?
35 mph east
42 mph east
60 mph east
85 mph east
Physics
2 answers:
egoroff_w [7]1 year ago
6 0

60 mph east...........

Ivan1 year ago
4 0

Answer:

The instantaneous velocity at any time during the second hour of the trip is 60 mph east

(C) is correct option

Explanation:

Given that,

Distance in first hour = 25 miles

Distance in second on hour = 60 miles

Instantaneous velocity :

Instantaneous velocity is equal to the distance divided by the time

We need to calculate the instantaneous velocity at any time during the second hour of the trip

Using formula of instantaneous velocity

.v = \dfrac{d}{t}

Where, d = distance

t = time

Put the value into the formula

v = \dfrac{60}{1}

v= 60\ miles/hr

The direction of the instantaneous velocity is in east .

Hence, The instantaneous velocity at any time during the second hour of the trip is 60 mph east

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2. Harry is pushing a car down a level road at 2.0 m/s with a force of 243 N. The total force
Arte-miy333 [17]

b) Equal to 243 N.

Explanation:

The total force acting on the car in the opposite direction including the road friction and air resistance is equal to 243 N.

This is in conformity with newton's third law of motion.

Newton's third law of motion states that "action and reaction are equal and opposite in direction. "

  • The action force is that of the pull by Harry acting on the car.
  • The reaction force is in the opposite direction.
  • Both action and reaction force equal and opposite and magnitude and direction

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

3 0
2 years ago
You throw a Frisbee of mass m and radius r so that it is spinning about a horizontal axis perpendicular to the plane of the Fris
Usimov [2.4K]

Answer:

Torque τ =w ×0 = 0

Explanation:

We know that the torque is given by the product of the force and perpendicular distance between the force and the axis.

Here the gravity force act at the center and the rotational axis is also passing through the center.

Therefore the perpendicular distance between the force and the rotational axis would be zero.

Hence the torque will be

Torque = Force × Perpendicular distance

Torque = mg×0 = 0

Therefore the torque would be zero.

7 0
1 year ago
Substance X is placed in a container with substance Y. Both substances are fluids. Substance X initially sinks to the bottom of
Brut [27]

Answer: Option (A) is the correct answer.

Explanation:

Convection is a process in which heat transfers from a hotter substance to a colder substance.

As a result, the substance which is less dense will rise and the more denser substance will sink due to the influence of gravity.

Thus, we can conclude that in the given situation substance X will rise due to convection.

3 0
2 years ago
Read 2 more answers
A seasoned mini golfer is trying to make par on a tricky number five hole. The golfer can complete the hole by hitting the ball
liberstina [14]

Answer:5.17 m/s

Explanation:

Given

let u be the speed at cliff initial point

range over cliff is 1.45 m

and range of projectile is given by

R=\frac{u^2\sin 2\theta }{g}

1.45=\frac{u^2\sin 90}{9.8}

u=3.77 m/s

Conserving Energy

E_{bottom}=E_{initial\ point\ at\ cliff}

Kinetic energy=Kinetic energy +Potential energy gained

Let v be the initial velocity

\frac{mv^2}{2}=mgh+\frac{mu^2}{2}

v^2=u^2+2gh

v=\sqrt{u^2+2gh}

v=\sqrt{3.77^2+2\time 9.8\times 0.64}

v=\sqrt{26.75}=5.17 m/s

5 0
1 year ago
How much energy does a 50 kg rock have if it is sitting on the edge of a 15 m cliff?
noname [10]

Answer:

7350 J

Explanation:

The gravitational potential energy of the rock sitting on the edge of the cliff is given by:

U=mgh

where

m is the mass of the rock

g is the gravitational acceleration

h is the height of the cliff

In this problem, we have

m = 50 kg

g = 9.8 m/s^2

h = 15 m

Substituting numbers into the formula, we find:

U=(50 kg)(9.8 m/s^2)(15 m)=7350 J

3 0
2 years ago
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