Recall that in the equilibrium position, the upward force of the spring balances the force of gravity on the weight is given below.
Explanation:
Measure unstretched length of spring, L. E.g. L = 0.60m.
Set mass to a convenient value (e.g. m = 0.5kg).
Hang mass.
Measure new spring length, L'. E.g. L' = 0.70m.
Calculate extension: e = L' - L = 0.70 – 0.60 = 0.10m
Use mg = ke (in equilibrium weight = tension)
k = mg/e
Don't know what value you are using for example. Suppose it is 10N/kg (same thing as 10m/s²).
k = 0.5*10/0.10 = 50 N/m
Repeat for a few different masses. (L always stays the same.)
Take the average of your k values.
Answer:
Column X. Tangential Speed
Column Y. radius
Explanation:
The equation for centripetal acceleration is
= v² / r
Where v is the tangential velocity of the body and the radius of curvature.
To analyze this equation you must place the tangential velocity in one column and in the other the turning radius
Let's check the answers
Column X. Tangential Speed
Column Y. radius
This is the correct answer.
Answer:
The change in the equilibrium melting point is 4.162 K.
Explanation:
Given that,
Pressure = 10 kbar
Molar volume of copper
Volume of liquid
Latent heat of fusion 
Melting point =1085°C
We need to calculate the change temperature
Using Clapeyron equation

Put the value into the formula



Hence, The change in the equilibrium melting point is 4.162 K.
Answer:
3.5 cm
Explanation:
mass, m = 50 kg
diameter = 1 mm
radius, r = half of diameter = 0.5 mm = 0.5 x 10^-3 m
L = 11.2 m
Y = 2 x 10^11 Pa
Area of crossection of wire = π r² = 3.14 x 0.5 x 10^-3 x 0.5 x 10^-3
= 7.85 x 10^-7 m^2
Let the wire is stretch by ΔL.
The formula for Young's modulus is given by


ΔL = 0.035 m = 3.5 cm
Thus, the length of the wire stretch by 3.5 cm.

The ball is against the vector of gravity. Then, the gravity will be negative.

The ball will stop in the air after approx. 4.72 seconds. And will take the same time to hit the ground.
It will stay approx. 9.44 seconds in the air.