answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sertanlavr [38]
2 years ago
13

A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.12

0 kg and length 80.0 cm .

Physics
2 answers:
den301095 [7]2 years ago
5 0

Question

Initially, the baton is spinning about a line through its center at angular velocity 3.00 rad/s.  What is its angular momentum? Express your answer in kilogram meters squared per second.

Answer:

0.0192 kgm^{2}/s

Explanation:

The angular momentum L of the baton moving about an axis perpendicular to it, passing through the center of the baton is,

L = \frac{1}{{12}}m{l^2}\omega

Here, l is the length of the baton.

Substitute 0.120 kg for m, 3 rads/s for \omega[\tex] and 0.8 m for l [tex]\begin{array}{c}\\L = \frac{1}{{12}}m{l^2}\omega \\\\ = \frac{1}{{12}}\left( {0.120{\rm{ kg}}} \right){\left( {{\rm{80}}{\rm{.0 cm}}} \right)^2}{\left( {\frac{{1 \times {{10}^{ - 2}}{\rm{m}}}}{{1{\rm{ cm}}}}} \right)^2}\left( {{\rm{3}}{\rm{.00 rad/s}}} \right)\\\\ = 0.0192{\rm{ kg}} \cdot {{\rm{m}}^{\rm{2}}}{\rm{/s}}\\\end{array}

maw [93]2 years ago
4 0

Its angular momentum is 0.0192 kg.m²/s

\texttt{ }

<h3>Further explanation</h3>

<u><em>Complete Question:</em></u>

<em>A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.120 kg and length 80.0 cm. Initially, the baton is spinning about a line through its center at angular velocity 3.00 rad/s. What is its angular momentum? Express your answer in kilogram meters squared per second</em>

<u>Given:</u>

mass of the baton = m = 0.120 kg

length of the baton = R = 80.0 cm = 0.8 m

angular velocity = ω = 3.00 rad/s

<u>Asked:</u>

angular momentum = L = ?

<u>Solution:</u>

L = I \times \omega

L = ( \frac{1}{12} m R^2 ) \omega

L = \frac{1}{12} m \omega R^2

L = \frac{1}{12} \times 0.120 \times 3.00 \times 0.8^2

L = \frac{12}{625}

L \approx 0.0192 \texttt{ kgm}^2\texttt{/s}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

\texttt{ }

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

You might be interested in
Pions have a half-life of 1.8 x 10^-8 s. A pion beam leaves an accelerator at a speed of 0.8c. What is the expected distance ove
Nuetrik [128]

Answer:

the expected distance is 4.32 m

Explanation:

given data

half life time = 1.8 × 10^{-8} s

speed = 0.8 c = 0.8 × 3 × 10^{8}

to find out

expected distance over

solution

we know c is speed of light in air is 3 × 10^{8} m/s

we calculate expected distance by given formula that is

expected distance = half life time × speed   .........1

put here all these value

expected distance = half life time × speed

expected distance = 1.8 × 10^{-8} ×  0.8 × 3 × 10^{8}

expected distance = 4.32

so the expected distance is 4.32 m

5 0
1 year ago
Which phrases describe NASA's goals in the coming years? Check all that apply.
Serggg [28]

Answer:

1, 3 and 4

Explanation:

Did the test and saw the answers.

3 0
2 years ago
Read 2 more answers
A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly hori
Nutka1998 [239]

Answer:

The cannonball fly horizontally before it strikes the ground, S = 323.25 m

Explanation:

Given data,

The height of the cliff, h = 80 m

The horizontal velocity of the cannonball, Vₓ = 80 m/s

The range of the cannon ball with initial vertical velocity is zero is given by the formula,

                           S=\frac{V_{x}\sqrt{2gh}}{g}

                           S=\frac{80\sqrt{2\times9.8\times80}}{9.8}

                           S = 323.25 m

Hence, the cannonball fly horizontally before it strikes the ground, S = 323.25 m

7 0
2 years ago
Read 2 more answers
A 0.200-kg mass attached to the end of a spring causes it to stretch 5.0 cm. If another 0.200-kg mass is added to the spring, th
ziro4ka [17]

Answer:

A: 4 times as much

B: 200 N/m

C: 5000 N

D: 84,8 J

Explanation:

A.

In the first question, we have to caculate the constant of the spring with this equation:

m*g=k*x

Getting the k:

k=\frac{m*g}{x} =\frac{0,2[kg]*9,81[\frac{m}{s^{2} } ]}{0,05[m]} =39,24[\frac{N}{m}]

Then we can calculate how much the spring stretch whith the another mass of 0,2kg:

x=\frac{m*g}{k} =\frac{0,4[kg]*9,81[\frac{m}{s^{2} } ]}{39,24[\frac{N}{m}]} =0,1[m]\\

The energy of a spring:

E=\frac{1}{2}*k*x^{2}

For the first case:

E=\frac{1}{2} *39,24[\frac{N}{m}]*(0,05[m])^{2} =0,049 [J]

For the second case:

E=\frac{1}{2} *39,24[\frac{N}{m}]*(0,1[m])^{2} =0,0196 [J]

If you take the relation E2/E1 = 4.

B.

We have the next facts:

x=0,005 m

E = 0,0025 J

Using the energy equation for a spring:

E=\frac{1}{2}*k*x^{2}⇒k=\frac{E*2}{x^{2} } =\frac{0,0025[J]*2}{(0,005[m])^{2} } =200[\frac{N}{m} ]

C.

The potential energy of the diver will be equal to the kinetic energy in the moment befover hitting the watter.

E=W*h=500[N]*10[m]=5000[J]

Watch out the units in this case, the 500 N reffer to the weighs of the diver almost relative to the earth, thats equal to m*g.

D.

The work is equal to the force acting in the direction of the motion. so we have to do the diference beetwen angles to obtain the effective angle where the force is acting: 47-15=32 degree.

The force acting in the direction of the ramp will be the projection of the force in the ramp, equal to F*cos(32). The work will be:

W=F*d=F*cos(32)*d=10N*cos(32)*10m=84,8J

7 0
1 year ago
Squid use jet propulsion for rapid escapes. A squid pulls water into its body and then rapidly ejects the water backward to prop
Setler [38]

Answer:

a. FTh = 30 N

b. Fw = 30 N

c. a = 200 m/s2

Explanation:

See full explanation in the picture. Please rate as brainliest

5 0
1 year ago
Other questions:
  • What is the kinetic energy of a 2000 kilogram boat moving at 5m/sec?
    12·1 answer
  • Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box, what is the magnit
    9·2 answers
  • myron is almost late for class and he is running quickly to arrive before the professor begins lecturing as he listen to the pro
    11·1 answer
  • Two small aluminum spheres, each of mass 0.0250 kilograms, areseparated by 80.0 centimeters.
    7·1 answer
  • You go to an amusement park with your friend Betty, who wants to ride the 70-m-diameter Ferris wheel. She starts the ride at the
    6·1 answer
  • What mass needs to be attached to a spring with a force constant of 7N/m in order to make a simple harmonic oscillator oscillate
    9·1 answer
  • : The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop
    11·1 answer
  • A very long uniform line of charge has charge per unit length λ1 = 4.80 μC/m and lies along the x-axis. A second long uniform li
    14·1 answer
  • The velocity of a car increases from 2.0 m/s to 16.0 m/s in a time period of 3.5 s. What was the average acceleration?
    13·2 answers
  • As an object in motion becomes heavier, its kinetic energy _____. A. increases exponentially B. decreases exponentially C. incre
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!