Impulse = Integral of F(t) dt from 0.012s to 0.062 s
Given that you do not know the function F(t) you have to make an approximation.
The integral is the area under the curve.
The problem suggest you to approximate the area to a triangle.
In this triangle the base is the time: 0.062 s - 0.012 s = 0.050 s
The height is the peak force: 35 N.
Then, the area is [1/2] (0.05s) (35N) = 0.875 N*s
Answer> 0.875 N*s
Answer:
xcritical = d− m1
/m2
( L
/2−d)
Explanation: the precursor to this question will had been this
the precursor to the question can be found online.
ff the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal bar may become unstable (i.e., the bar may no longer remain horizontal). What is the smallest possible value of x such that the bar remains stable (call it xcritical)
. from the principle of moments which states that sum of clockwise moments must be equal to the sum of anticlockwise moments. aslo sum of upward forces is equal to sum of downward forces
smallest possible value of x such that the bar remains stable (call it xcritical)
∑τA = 0 = m2g(d− xcritical)− m1g( −d)
xcritical = d− m1
/m2
( L
/2−d)
Answer:
13.9
Explanation:
Apparent weight is the normal force. Sum of the forces on the alloy when it is submerged:
∑F = ma
N + B − W = 0
N + ρVg − mg = 0
6.6 + (0.78 × 1000) V (9.8) − (0.750) (9.8) = 0
V = 9.81×10⁻⁵
If x is the volume of the first material, and y is the volume of the second material, then:
x + y = 9.81×10⁻⁵
(7.87×1000) x + (4.50×1000) y = 0.750
Two equations, two variables. Solve with substitution:
7870 (9.81×10⁻⁵ − y) + 4500 y = 0.750
0.772 − 7870 y + 4500 y = 0.750
0.0222 = 3370 y
y = 6.58×10⁻⁶
x = 9.15×10⁻⁵
The ratio of the volumes is:
x/y = 13.9
Out of all given choices, activities and donor list can be found on the given kind of informative website.
Answer: Option A and B
<u>Explanation:</u>
Non-profit need to do the examination and for sake activities that simply aren't successful. And afterwards, they have to look to a portion of these auxiliary changes that to discover increasingly productive approaches to make a feasible money related model for their social change work.
When occasions are crucial, allowed to visit, and concentrated on developing as well as managing present or potential significant donors (people, establishments, corporate pioneers, they can bode well. Yet, only in the event that you catch up with participants on a one-on-one premise to additionally put them in the association and in the long run request that they contribute or reestablish their commitments.
On the off chance, you don't charge those to visit with the goal that can approach them for a greater, and progressively important blessing not far off.
Answer:
It cancels recoil.
Explanation:
For each action there is an equal an opposite reaction.
The principle of conservation of momentum tell us that if a single spore were ejected the fern would suffer a recoil from it. This recoil would take energy and speed from the spore. But if they are ejected in pairs the recoil is canceled and all the energy is transferred to the spores resulting in higher speeds.
