A quarterback throws a football at 40km/hr to a receiver 50yd away. How much time does it take the ball to reach the receiver
1 answer:
Given:
Distance = 50 yard = 45.72 meter
Speed = 40 km/hr = 11.11 m/s
To find:
Time required by ball to reach the receiver = ?
Formula used:
speed =
Solution:
The speed of the ball is given by,
speed =
Thus,
Time =
Distance = 50 yard = 45.72 meter
Speed = 40 km/hr = 11.11 m/s
Time = 4.12 second
Hence, ball reaches the receiver in 4.12 second.
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Answer:
1 angstrom = 0.1nm
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Answer:
A). σ = 3.823 x
/N-
B). C/
C). J
Explanation:
A). We know magnitude of charge per unit area for a conducting plate is given by
where, E is resultant electric field = 1.2 x V/m
is permittivity of free space = 8.85 x
/N-
k is dielectric constant = 3.6
∴
= 3.6 x 8.85 x x 1.2 x
= 3.823 x
/N-
B).Now we know that the magnitude of charge per unit area on the surface of the dielectric plate is given by
C/
C).
Area of the plate, A = 2.5
= 2.5 x
diameter of the plate, d = 1.8 mm
= 1800 m
∴ Total energy stored in the capacitor
J