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2 years ago

10

You are stranded in a blizzard. You need water to drink to drink,and you're trying to stay warm.should the melt the snow and dri

nk it or just eat the snow? Explain

1 answer:

Crazy boy [7]2 years ago

7 0

It would be a really bad idea to eat the snow because you obviously are trying to stay warm right? Well, the best thing to do is melt the snow. However, the process of melting the snow would have a few complications as well. But yes, the latter idea (drinking the snow) is a better idea (not the best).

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If a 0.15 kg ball on the end of a string is swung in a vertical circle of radius .6 meters and makes 2 revolutions per second, w

Marina CMI [18]

Answer:

12.7 N

15.7 N

Explanation:

mass (m) = 0.15 kg

radius (r) = 0.6 m

speed = 2 rps = 2 x 60 = 120 rpm

acceleration due to gravity (g) = 9.8 m/s^{2}

find the tension at the top and bottom of the circle.

Tension at the top T = $\frac{mv^{2} }{r} - mg$

where v = speed in m/s

v = radius x rpm x 0.10472 = 0.6 x 120 x 0.10472 = 7.54 m/s

we can now substitute the value of v into T = $\frac{mv^{2} }{r} - mg$

T = $\frac{0.15x7.54^{2} }{0.6} - (0.15x9.8)$ = 12.7 N

Tension at the bottom T' = $\frac{mv^{2} }{r} + mg$

where v = speed in m/s

v = radius x rpm x 0.10472 = 0.6 x 120 x 0.10472 = 7.54 m/s

we can now substitute the value of v into T' = $\frac{mv^{2} }{r} + mg$

T' = $\frac{0.15x7.54^{2} }{0.6} + (0.15x9.8)$ = 15.7 N

4 0

2 years ago

A particle of mass m moves in the xy plane with a velocity of v = vxî + vyĵ. Determine the angular momentum of the particle abou

alexira [117]

Answer:

$L=m(xv_y-yv_x)k$

Explanation:

It is given that,

Velocity of a particle, $v=v_xi+v_yj$

Position vector of a particle, $r=xi+yj$

We need to find the angular momentum of the particle. It is given by :

$L=r\times p$ , p = linear momentum

$L=r\times (mv)$

$L=m(r\times v)$

$L=m((xi+yj)\times (v_xi+v_yj))$

$L=m(xv_y-yv_x)k$

So, the angular momentum of the particle is $(xv_y-yv_x)k$ . Hence, this is the required solution.

5 0

2 years ago

a powerboat accelerates along a straight path from 0 km/hr to 99.8 km/hr in 10.0 s.Find the average acceleration of the boat in

Alex777 [14]

(27.72-0)/10
= 2.772 m/s2

3 0

2 years ago

A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar

finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

$\displaystyle V=k\frac{Q}{r}$

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

$d=\sqrt2 a$

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

$\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}$

$\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m$

The total potential is

$V_t=V_1+V_2+V_3+V_4$

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of $\pm 3\mu\ C$ . Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

$\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}$

$V_1=V_2=50912\ V$

The total potential is

$V_t=50912\ V+50912\ V=1\times 10^5\ V$

$\boxed{V_t=1\times 10^5\ V}$

6 0

2 years ago

The period of a pendulum is the time it takes the pendulum to swing back and forth once. If the only dimensional quantities that

Vinvika [58]

Explanation:

Let T is the period of a pendulum. The SI unit of time is seconds (s).

It depends on the acceleration of gravity, g, and the length of the pendulum, l.

The SI unit of acceleration of gravity, g and the length of the pendulum, l are m/s² and m respectively.

If we divide m and m/s², we left with s². If the square root of s² is taken, we get s only i.e. the SI unit of period of a pendulum.

So,

$T\propto \sqrt{\dfrac{l}{g}}$

Hence, this is the required solution.

7 0

2 years ago