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Monica [59]
2 years ago
5

A charge of 4.9 x 10-11 C is to be stored on each plate of a parallel-plate capacitor having an area of 150 mm2 and a plate sepa

ration of 3.3 mm. Also, the value of ε0 is 8.85 x 10-12 F/m. (a) What voltage (in V) is required if a material having a dielectric constant of 6.3 is positioned within the plates?
Physics
1 answer:
Triss [41]2 years ago
7 0

Answer:2.53*10^-10F

Explanation:

C=£o£r*A/d

Where £ is the permitivity of a constant

£o= 8.85*10^-12f/m

£r=6.3

A=150mm^2=0.015m^2

d=3.3mm= 0.0033m

C=8.85*10^-12*6.3*0.015/0.0033

C=8.85*6.3*10^-12*0.015/0.0033

C=55.755*0.015^-12/0.003

C=8.36/3.3*10^-13+3

C=2.53*10^-10F

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