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vampirchik [111]
2 years ago
11

A force of 150 N accelerates a 25 kg wooden chair across a wood floor at 4.3 m/s2 . How big is the frictional force on the block

? What is the coefficient of friction between the chair and floor?
Physics
1 answer:
solniwko [45]2 years ago
4 0
We can first calculate the net force using the given information.

By Newton's second law, F(net) = ma:

F(net) = 25 * 4.3 = 107.5

We can now calculate the frictional force, f, which is working against the applied force, F(app) (this is why the net force is a bit lower):

f = F(net) - F(app) = 150 - 107.5 = 42.5 N

Now we can calculate the coefficient of friction, u, using the normal force, F(N):

f = uF(n) --> u = f/F(N)
u = 42.5/[25(9.8)]
u = 0.17
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Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer
kodGreya [7K]

The peak wavelength of Betelgeuse is 828 nm

Explanation:

The relationship between surface temperature and peak wavelength of a star is given by Wien's displacement law:

\lambda=\frac{b}{T}

where

\lambda is the peak wavelength

T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot K is Wien's constant

For Betelgeuse, the surface temperature is approximately

T = 3500 K

Therefore, its peak wavelength is:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

Learn more about wavelength:

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#LearnwithBrainly

8 0
2 years ago
What results when energy is transformed while juggling three bowling pins?
Nady [450]

Answer:

his is an example of the transformation of gravitational potential energy into kinetic energy

Explanation:

The game of juggling bowling is a clear example of the conservation of mechanical energy,

when the bolus is in the upper part of the path mechanical energy is potential energy; As this energy descends, it becomes kinetic energy where the lowest part of the trajectory, just before touching the hand, is totally kinetic.

At the moment of touching the hand, a relationship is applied that reverses the value of the speed, that is, now it is ascending and the cycle repeats.

Therefore this is an example of the transformation of gravitational potential energy into kinetic energy

8 0
1 year ago
1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te qued
Kipish [7]

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}

Ahora cuando te doy 3/4 kg te queda en total:

m_{T} = \frac{1}{4} + \frac{3}{4} = 1 kg

Por lo tanto, tienes 1 kg de fruta al final.

2. Si falta por recorrer la mitad de la mitad, tenemos:

d = \frac{1/2}{2} = \frac{1}{4}

Entonces, queda por recorrer 1/4 km.

3. El peso (P) del hierro es:

P = m*g    

P = (1 + 1/2)kg*9.81 m/s^{2} = 14.72 N

Y el peso de la paja es:

P = 3/2 kg*9.81 m/s^{2} = 14.72 N

Por lo tanto, ambos pesan lo mismo.

Espero que te sea de utilidad!

6 0
2 years ago
A new class of objects can be created conveniently by ________; the new class (called the ________) starts with the characterist
iVinArrow [24]

Answer:

Option A is correct.

Inheritance, superclass, subclass

A new class of objects can be created conveniently by **inheritance**; the new class (called the **superclass**) starts with the characteristics of an existing class (called the **subclass**), possibly customizing them and adding unique characteristics of its own.

Explanation:

A class is a term in object oriented programming that is extensible program code used to create, name and implement what you want the objects to do.

Inheritance is used to describe the making of new classes from already existing classes. The general properties of the old classes remain in the new classes created from them.

Hence, the new classes (because they're usually an improvement on the old classes as they hold on to the wanted properties of the old classes and additional great ones are added or modified) are called superclasses and the old, already existing ones are called subclasses.

3 0
2 years ago
A heat engine absorbs 64 kcal of heateach cycle and exhausts 42 kcal. Calculate the efficiency of eachcycle. (Page Ref: Sec. 15.
Dahasolnce [82]

Answer:

The efficiency of each cycle of a heat engine is 30 %.                                                            

Explanation:

Given that,

Heat absorbed by a heat engine, Q = 64 kcal

Heat exhaust by a heat engine, Q' = 42 kcal

We need to find the efficiency of each cycle. The efficiency of heat engine is defined as the ratio of work output to the energy supplied. It is given by :

\eta=1-\dfrac{Q'}{Q}

\eta=1-\dfrac{42}{64}

\eta=0.3

or

\eta=30\%

So, the efficiency of each cycle of a heat engine is 30 %. Hence, this is the required solution.

4 0
2 years ago
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