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2 years ago

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A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Igno

ring viscous losses, what is the speed of water flowing through the crack? (b) How many cubic meters per second of water leave the dam?

1 answer:

vova2212 [387]2 years ago

3 0

Answer

given,

height of the dam = 15 m

effective area of water = 2.3 x 10⁻³ m²

Using energy conservation

$m g h = \dfrac{1}{2}mv^2$

$v= \sqrt{2gh}$

$v= \sqrt{2\times 9.8 \times 15}$

$v= \sqrt{294}$

v = 17.15 m/s

discharge of water

Q = A V

Q = 2.3 x 10⁻³ x 17.15

Q = 0.039 m³/s

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