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hammer [34]
2 years ago
8

A transformer is to be designed to increase the 30 kV-rms output of a generator to the transmission-line voltage of 345 kV-rms.

If the primary winding has 80 turns, how many turns must the secondary have?
Physics
1 answer:
Rufina [12.5K]2 years ago
4 0

Answer:

n_s = 920 \turns

Explanation:

given,

Voltage across the primary coil (V_p) = 30 kV-rms

Voltage across the secondary coils (V_s) = 345 kV-rms

number of turns primary coil have (n_p) = 80 turns

number of turns in secondary coil (n_s) = ?

the ratio of primary and secondary loop

     \dfrac{n_p}{n_s} = \dfrac{V_p}{V_s}

     \dfrac{n_s}{n_p} = \dfrac{V_s}{V_p}

     n_s = n_p \dfrac{V_s}{V_p}

     n_s = 80\times \dfrac{345}{30}

     n_s = 80\times 11.5

     n_s = 920 \turns

turns that secondary loop have is equal to n_s = 920 \turns

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