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2 years ago

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A transformer is to be designed to increase the 30 kV-rms output of a generator to the transmission-line voltage of 345 kV-rms.

If the primary winding has 80 turns, how many turns must the secondary have?

1 answer:

Rufina [12.5K]2 years ago

4 0

Answer:

$n_s = 920 \turns$

Explanation:

given,

Voltage across the primary coil (V_p) = 30 kV-rms

Voltage across the secondary coils (V_s) = 345 kV-rms

number of turns primary coil have (n_p) = 80 turns

number of turns in secondary coil (n_s) = ?

the ratio of primary and secondary loop

$\dfrac{n_p}{n_s} = \dfrac{V_p}{V_s}$

$\dfrac{n_s}{n_p} = \dfrac{V_s}{V_p}$

$n_s = n_p \dfrac{V_s}{V_p}$

$n_s = 80\times \dfrac{345}{30}$

$n_s = 80\times 11.5$

$n_s = 920 \turns$

turns that secondary loop have is equal to $n_s = 920 \turns$

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