What is the magnitude of the force between a 25μC charge exerts on a -10μC charge 8.5cm away?

Physics

1 answer:

Reil [10]1 year ago

7 0

Answer:

Force,

$F = \frac{kQ_{1} Q_{2} }{ {r}^{2} } \\ F = \frac{(9 \times {10}^{9}) \times (25 \times {10}^{ - 6}) \times (10 \times {10}^{ - 6} ) }{ {(0.85)}^{2} } \\ \\ F = 3.114 \: newtons$

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