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2 years ago

The Pickering nuclear power plant has a power rating of 3100 MW.

Physics

1 answer:

Roman55 [17]2 years ago

5 0

Answer:

$2.68\cdot 10^8 MJ$

Explanation:

The power is related to the energy by

$P=\frac{E}{t}$

where

P is the power

E is the energy

t is the time elapsed

The power of this nuclear power planet is

$P=3100 MW = 3.1\cdot 10^9 W$

The time we are considering is 1 day, which is

$t = 1 d = 86400 s$

So we can re-arrange the previous equation to find the energy produced by the power plant in one day:

$E=Pt =(3.1\cdot 10^9 W)(86400 s)=2.68\cdot 10^{14} J=2.68\cdot 10^8 MJ$

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A dog travels north for 18 meters, east for 8 meters, South for 27 meters and then west for 8 meters. What is the distance the d

Afina-wow [57]

I'm really not sure if this is right but I'll try.
The distance that the dog traveled is probably all of the distances added up. I would guess that it's 67 meters in total.
The displacement is a little more tricky but you pretty much have to put a mental map in your head. Since East and West are both 8 meters, they cancel each other out. He travels more southern and that means the displacement is 9 meters south of his original location

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2 years ago

A pulley 12 cm in diameter is free to rotate about a horizontal axle. A 220-g mass and a 470-g mass are tied to either end of a

Aleks [24]

Answer:0.147 N-m

Explanation:

Given

Diameter of Pulley $d=12 cm$

radius $r=6 cm$

mass of first object $m_1=220 gm$

mass of second object $m_2=470 gm$

Now both masses will exert a torque a on Pulley

Torque due to first Pulley $T_1=m_1g\cdot r$

$T_1=0.22\times 9.8\times 0.06=0.129 N-m$

Torque due to second mass on Pulley $T_2=m_2g\cdot r$

$T_2=0.276 N-m$

Total Torque by masses $T_{net}=T_2-T_1$

$T_{net}=0.276-0.129=0.147 N-m$

so we need to apply a torque of magnitude 0.147 N-m opposite to the direction of $T_{net}$

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2 years ago

Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another

ioda

Answer:

$6.1875\times 10^{-8}$

Explanation:

Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies $I=\frac {k}{r^{2}}$ where r is the distance