You didn't say so, but we must assume that the "200 km/hr" is
the glider's air-speed, that is, speed relative to the air.
If the air itself is moving at 30 km/hr relative to the ground and
across the glider's direction, then the glider's speed relative to
the ground is
√(200² + 30²)
= √(40,000 + 900)
= √(40,900) = 202.24... km/hr (rounded)
Answer:
Separation increases at all times that rock X falls because it falls with a greater speed
Explanation:
For both rocks, let initial velocity ∪=0
To find the displacement at any given time interval of Δt then
S= ∪Δt +0.5gΔt²
Since rock X is first released followed by Y, then X has a greater speed than Y therefore the distance covered by X is longer. This is because despite 0.5gΔt² being same for both rocks at any time Δt but rock X having already attained some velocity, its ∪Δt is more hence the separation S increases. Conclusively, S increases at all times that rock X falls since rock X falls with a greater velocity than rock Y
<span>You are given an applied force of 110 n with an angle of 30</span>°<span> with the ground. Since the force is not perpendicular or parallel to the sled then you will have two components. These components are in sine and cosine form.
for parallel component
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26
for the perpendicular component
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
Answer:
Explanation:
When a pair of medial has greater difference between the their individual refractive indices with respect to vacuum then it has a greater deviation between the refracted ray and the incident ray.
According to the Snell's law:
a)
b)
c)
d)
e)
f)
