Answer:
= 829.69 Watt
≅ 830 Watt
Explanation:
Given that,
Velocity of air flow = 12.5m/s
Rate of flow of air = 9m³/s
Density of air = 1.18kg/m³
power by kinetic energy = 1/2(mv²)
mass = density × volume
m = 1.18 × 9
= 10.62 kg/s
power = 1/2 mV²
= 1/2 (10.62 × 12.5²)
= 829.69 Watt
≅ 830 Watt
Flow rate
u
=
9
m
3
/
s
Velocity of the air
V
=
8
m/s
Density of the air
ρ
=
1.18
kg
/
m
3
Answer:
IV: type of shampoo used
DV: what shampoo made her hair the skinniest
control: water
Constant: rated from scale from 1-10
Explanation:
Answer:
The resistance will be 2×R
Explanation:
We note that the resistivity of a cylindrical wire is given by the following relation;

Where:
ρ = Resistivity of the wire
R = The wire resistance
A = Cross sectional area of the wire = π·D²/4
L = Length of the wire
Rearranging, we have;

If the length and the diameter are both cut in half, we have;
L₂ = L/2
A₂ =π·D₂²/4 =
Therefore, the new resistance, R₂ can be expressed as follows;

Hence, the new resistance R₂ = 2×R, that is the resistance will be doubled.
The answer for this question, If I am correct, should be answer "D".