answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bearhunter [10]
2 years ago
14

Tendons are strong elastic fibers that attach muscles to bones. To a reasonable approximation, they obey Hooke's law. In laborat

ory tests on a particular tendon, it was found that, when a 251 g object was hung from it, the tendon stretched 1.23 cm .Find the force constant of this tendon.
Physics
1 answer:
meriva2 years ago
5 0

Answer:

k = 200 N/m

Explanation:

given,

mass of the object  = 251 g

                                = 251 x 10⁻³ Kg = 0.251 Kg

distance of tendon stretch = x = 1.23 cm

                                            = 1.23 x 10⁻² = 0.0123 m

using the formula

F = k  x

where

k is the force constant of the tendon

F = m g

F = 0.251 x 9.8 = 2.4598 N

2.4598 = k x 0.0123

k = 199.98 N/m

k = 200 N/m

hence, force constant of the tendon is approximately equal to 200 N/m

You might be interested in
a cannonball with a mass of 1.0 kilogram is fired horizontally from a 500.- kilogram cannon, initially at rest, on a horizontal,
nirvana33 [79]

(a) According to Newton’s third law, for every action there is an equal yet opposite reaction. In this case, the cannonball is affected by 8.0x10^3 newtons in one direction. Now the cannon must also be affected by the same amount of net force on the opposite direction.

- 8.0x10^3 Newtons (the negative symbol only shows that it is opposite direction)

 

(b) We solve this using the formula:

F = m a

8.0x10^3 N = (1.0 kg) a

a = 8,000 m/s^2

8 0
2 years ago
A hammer of mass M is moving at speed v0 when it strikes a nail of negligible mass that is stuck in a wooden block. The hammer i
OleMash [197]

Answer:

i think it would be D

8 0
2 years ago
Suppose you have designed a new thermometer called the x thermometer. on the x scale the boiling point of water is 129 ∘x and th
gladu [14]

For any temperature scale the ratio of difference of temperature will be same

so we can write

\frac{T^ox - 12^ox}{129^ox - 12^ox} = \frac{T^of - 32^of}{212^of - 32^of}

now given that in both scales the temperature must be same

\frac{T^ox - 12^ox}{117^ox} = \frac{T^of - 32^of}{180^of}

T - 12 = 0.65 (T - 32)

0.35T = -8.8

T = -25.14 ^ox

<em>so at above temperature both scales will have same temperature</em>

8 0
2 years ago
A disk is free to rotate about an axis perpendicular to the disk through its center. If the disk starts from rest and accelerate
garri49 [273]

Answer:

(C) 16 radians

Explanation:

The angular displacement is given by the following equation:

\Delta \theta=\omega_i t+\frac{1}{2}\alpha t^2

Here

\Delta \theta Is the angular displacement of the body at the indicated time (t).

\omega_i Is the angular velocity of the body at the initial moment.

\alpha Is the angular acceleration of the body.

The disk starts from rest, so \omega_i=0

Replacing the given values:

\Delta \theta=\frac{1}{2}(2\frac{radians}{s^2})(4s)^2\\\Delta \theta=16 radians

3 0
2 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
LuckyWell [14K]

For a circular aperture, the first minima (n=1) as an angular separation from the peak of the central maxima given by

Sinθ = 1.22λ / d

Where,

d is the aperture or pupil diameter

d = 4.69 mm = 4.69 × 10^-3m

λ is the wavelength

λ = 545 nm = 545 × 10^-9 m

Then,

Sinθ = 1.22λ / d

Sinθ = 1.22 × 545 × 10^-9 / 4.69 × 10^-3

Sinθ = 1.418 × 10^-4 rad

Then, the head light sources have the same angular separation θ from the eye as the image have inside the eye.

For the headlight

Sinθ ≈ light separation / distantce for the eye

Light separation is give as x = 0.659 m

And let the distance of the eye be D

Then,

Sinθ = x / D

Make D subject of formula

D = x / Sinθ

D = 0.695 / 1.418 × 10^-4

D = 4902.316m

To km, 1km = 1000m

D ≈ 4.9 km

4 0
2 years ago
Other questions:
  • a rod of some material 0.20 m long elongates 0.20 mm on heating from 21 to 120°c. determine the value of the linear coefficient
    10·1 answer
  • Where do incident rays that are parallel to the principal axis converge to after reflecting off a concave mirror?
    14·1 answer
  • A spaceship is travelling at 20,000.0 m/s. After 5.0 seconds, the rocket thrusters are turned on. At the 55.0 second mark, the s
    9·1 answer
  • A 38 kg crate rests on a floor. A horizontal pulling force of 170 N is needed to start the crate
    15·1 answer
  • To practice Problem-Solving Strategy 29.1: Faraday's Law. A metal detector uses a changing magnetic field to detect metallic obj
    6·1 answer
  • A ship sends out a 1200 Hz sound wave, which has a wavelength of 120 cm in the water. What would happen if that ship sent out a
    6·1 answer
  • A student placed an ice cube on a table and observed it for five minutes. He noticed that the ice cube seemed to get smaller and
    14·1 answer
  • g The international space station has an orbital period of 93 minutes at an altitude (above Earth's surface) of 410 km. A geosyn
    13·1 answer
  • Nuclear waste disposal is one of the largest issues with nuclear power. Cesium-137 is one of the high level waste products in an
    7·1 answer
  • Which season is signaled by average lower temperature and indirect, angled sunlight?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!