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1 year ago

6

where again p is the phonon momentum, E is the photon energy and c is the speed of light. When you divide the photon energy foun

d in #6 by the photon momentum found in #4, do you get the speed of light? (If not, check your work for questions #4 through #6).

1 answer:

creativ13 [48]1 year ago

8 0

Answer:

Yes

Explanation:

p = momentum of photon

E = energy of photon

c = velocity of light

Units of p = kg m /s

Units of E = kg m^2 / s^2

Units of E / p = {kg m^2 / s^2} / {kg m /s} = m/s

It is the unit of speed, so by the division of energy to the momentum, we get the speed. yes it is correct.

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As we know that

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now in order to find the work done

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What type of roadway has the highest number of hazards per mile?

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1 year ago

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Answer:

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Given:

Mass of block $m = 6.60$ kg

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Final speed of block $v_{f} = 0$ $\frac{m}{s}$

Coefficient of kinetic friction $\mu _{k} = 0.62$

Ramp inclined at angle $\theta =$ 28.4°

Using conservation of energy,

Work done by frictional force is equal to change in energy,

$\mu _{k} mgd \cos 28.4 = \Delta K - \Delta U$

Where $\Delta U = mg d\sin 28.4$

$\mu _{k} mgd \cos 28.4 = \frac{1}{2}mv_{i} ^{2} - mgd\sin 28.4$

$\mu _{k} mgd \cos 28.4 +mgd\sin 28.4 = \frac{1}{2}mv_{i} ^{2}$

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2 years ago

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Answer:

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